Question

Please help me out :)

Answer 1

Answer:

$\frac{\sqrt{17} }{7}$

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx = $\sqrt{1-cos^2x}$

Note that ($\frac{4\sqrt{2} }{7}$)² = $\frac{32}{49}$

sinΘ = $\sqrt{1-(32/49)}$

        = $\sqrt{\frac{17}{49} }$ = $\frac{\sqrt{17} }{7}$