From the given graph, we can say that the equation of the graph is
which can also be written as
Comparing it with slope intercept form, that is
we will get slope equals to 0 .
So the correct option is the third option .
Please help me out :)
1 answer:
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The graph shows a piecewise function, meaning that different functions are shows at different intervals (ranges of x-values).
1) One of the graphs is part of a parabola, meaning the equation is quadratic (has
). That equation must be 
.
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.
Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1)
Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2
2)
Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it
------
Answer: C)
1) One of the graphs is part of a parabola, meaning the equation is quadratic (has
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.
Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1)
Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2
2)
Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it
------
Answer: C)
