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3 years ago

10

Help fast please !! Represent the following sentence as an algebraic expression, where "a number" is the letter x. 4 is added to

twice a number.

1 answer:

Oduvanchick [21]3 years ago

5 0

The answer is 2x + 4 :)

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3 years ago

A(n) __________ equation is an equation that involves one or more absolute value expressions.

mestny [16]

J can give you some example:
absolute (1-3)=absolute(-2)=2

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3 years ago

What is the measures of N<br>

Lubov Fominskaja [6]

Answer:provides that the voter approval requirement would not apply where the General Plan amendment is necessary to comply with state or federal housing law, including, but not limited to, affordable housing requirements.

Step-by-step explanation:

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3 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

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3 years ago

Please answer this question now

larisa [96]

Answer:

1471.15

Step-by-step explanation:

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3 years ago