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Arturiano [62]
3 years ago
9

Find the missing side length of the right triangle shown. Round to the nearest tenth, if

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0

Answer:

26 inch

Step-by-step explanation:

unknown side can be found using Pythagorean theorem

a*a+b*b=c*c

24*24+10*10=c*c

576+100=c*c

√676=c

c=26inche

Delvig [45]3 years ago
4 0

Answer:

? = 26 in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )

? = \sqrt{676} = 26

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I think it's B but I'm not sure

5 0
3 years ago
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20 points! I need the answer ASAP! Thanks!
serious [3.7K]

Answer: y=5/7x+2

Step-by-step explanation:

The y- intercept would be 2 since that is where the line goes through the y axis. Also if you use slope form you will see that the slope is 5/7.

5 0
3 years ago
A student has received the following test scores: 71%, 89%, 72%,
lidiya [134]

Answer: 81%

Step-by-step explanation:

From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,

84% and 83% in 5 tests and the student wants to maintain an average of 80%.

The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:

First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:

= 80 × 6

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We then add all the 5 test scores. This will be:

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5 0
4 years ago
-1y + 11= 20 what is the answer 3 or -3
yan [13]

Answer:

-9

Step-by-step explanation:

-1y+11=20

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8 0
3 years ago
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Find the values of x and y.
vova2212 [387]

Look at the picture.

We have the equation (1) 12x + 4y = 40.

We know, the sum of the acute angles in a right triangle is 90°.

Therefore we have the equation (2) (12x + 4y) + (17x - y) = 90

Substitute (1) to (2):

40 + 17x - y = 90        <em>subtract 40 from both sides</em>

17x - y = 50   (3)

We have the system of equations:

\left\{\begin{array}{ccc}12x + 4y = 40&|:4\\17x-y=50\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3x + y = 10\\17x-y=50\end{array}\right}\ \text{add both side of equations}\\.\qquad20x=60\qquad|:20\\.\qquad x=3

Substitute the value of x to (3)

17(3)-y=50\\51-y=50\qquad|-51\\-y=-1\to y=1

Answer: x = 3 and y = 1.

4 0
3 years ago
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