a.
Solution Given:
Slope of the line passing through the point is
m=
<u>slope=-2</u>
b.
Solution given:
equation is
2x-5y=-10
2x+10=5y
y=2x/5 +10/5
y=2/5 x +3
comparing above equation with y=mx+c
we get
m=2/5
<u>slope=2/5</u>
c.
Slope of the line passing through the point is
m=
-4=
-4=10/-x
doing criss cross multiplication
-4*-x=10
4x=10
x=10/4
x=5/2
<u>slope=5/2</u>
d.
we have
equation of line passing through the one point is
y-5=-7(x-(-1))
y=-7(x+1)+5
y=-7x-7+5
<u>y=-7x-2 is a required equation:</u>
Answer:
x = 0
Step-by-step explanation:
-[(3^x - 1)(5^x - 1)] + 1 = 1
Subtract 1 form both sides
-[(3^x - 1)(5^x - 1)] = 0
Divide both sides by -1
(3^x - 1)(5^x - 1) = 0
Equate the factors to 0
3^x - 1 = 0
3^x = 1
Use ln both sides
ln(3^x) = ln(1)
xln(3) = 0
x = 0
5^x - 1 = 0
5^x = 1
Use ln both sides
ln(5^x) = ln(1)
xln(5) = 0
x = 0
The only solution is x = 0
I am not sure about the answer but all you have to think about is what is 100 divided by 3
Given:
The surface area of a right circular cone is 32 sq. cm.
Scale factor for enlargement = 3
To find:
The surface area of the new cone.
Solution:
We know that enlargement of a shape forms a similar shape and area of the similar shapes is proportional to the square of their corresponding sides.
Let the surface area of new cone be A and r be the radius of original cone
By cross multiplication, we get
The surface area of the new cone is 288 sq. cm.
Therefore, the correct option is C.