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NikAS [45]
3 years ago
5

Use the fuction h(x)=5x-2 and t(x) =4x+6 to complete the fuction operations listed below

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0
Part A
(h + t)(x)
(5x - 2 + 4x + 6)(x)   First plug in the numbers
(9x + 4)(x)   Add h(x) and t(x)
(9x² + 4x)   Then multiply it by x
x(9x + 4)   Lastly, simplify x out (I'm including both answers because I don't know whether your questions will ask for either one)
Unsimplified Answer: 9x² + 4x      Simplified Answer: x(9x + 4)

Part B
(h x t)(x)
(5x - 2)(4x + 6)(x)    First step is to of cource, plug in the numbers
(20x² + 30x -8x -12)(x)   Next we multiply h(x) and t(x)
(20x² + 22x -12)(x)     Simplify it a little
(20x³ + 22x² - 12x)    After that, multiply the whole thing by x
(2x)(10x² + 11x - 6)     Simplify 2x out of the equation
(2x)(5x - 2)(2x + 3)    Lastly, simplify the rest
Unsimplified Answer: (20x³ + 22x² -12x)    Simplified Answer: (2x)(5x - 2)(2x + 3)

Part C
h[t(x)]
(5x - 2) [(4x + 6)(x)]    Plug in the numbers
(5x - 2)(4x² + 6x)       Multiply t(x) and x
(20x³ + 30x² - 8x² -12x)    Multiply that by h(x)
(20x³ + 22x² -12x)     Simplify a little... Wait! That looks like the answer to Part B! Perhaps we did something wrong, let's go back and alter the third step
(5x -2)(2x)(2x + 3)     This time, simplify before multiplying oh wait, that's part B's simplified answer, isn't it.
Well, there's a good explanation for this: Part B and Part C are essentially the same equations, just in slightly different orders!
So, it will have the same answers and Part B! (At least, in theory, I'd recommend checking this for yourself too!)
Unsimplified Answer: (20x³ + 22x² - 12x)   Simplified Answer: (2x)(5x-2)(2x+3)

Well, that's a wrap, Parts A, B, and, C with work and explanations; if you find that I made a mistake or did something wrong let me know. I hope this helped, and good luck!
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Answer: 22

Step-by-step explanation:

11 - 6 = 5

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' pls can i have brainliest? i need it for my goal'

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What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
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Let equation be Ax+By+C=0
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B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
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or equivalently
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Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




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Answer:

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Step-by-step explanation:

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