Answer:x=-2
Step-by-step explanation: -1=3/2x+2
here
p= 15000
r=15%
t= 3 yrs
now
depreciation = p(1-r/100)^t
= 15000(1-15/100)^3
=9211.875
=9212 or 9211.88
Answer:
Global prevalence among adults (the percent of people ages 15-49 who are infected) has leveled since 2001 and was 0.8%in 2018 (see Figure 1).
There were 37.9 millionpeople living with HIV in 2018 (see Table 1), up from 31.7 million in 2010, the result of continuing new infections and people living longer with HIV. Of the people living wi...
Although HIV testing capacity has increased over time, enabling more people to learn their HIV..
Answer:
6
Step-by-step explanation:
Cost per item is found by dividing the cost by the number of items. If the woman bought n items for $120, the cost of each item is $120/n. If the woman bought 24 more items, n+24, at the same price, then the cost per item is $120/(n+24). The problem statement tells us this last cost is $16 less than the first cost:
120/(n+24) = (120/n) -16
Multiplying by n(n+24) gives ...
120n = 120(n+24) -16(n)(n+24)
0 = 120·24 -16n^2 -16·24n . . . . . . subtract 120n and collect terms
n^2 +24n -180 = 0 . . . . . . . . . . . . . divide by -16 to make the numbers smaller
(n +30)(n -6) = 0 . . . . . . . . . . . . . . factor the quadratic
The solutions to this are the values of n that make the factors zero: n = -30, n = 6. The negative value of n has no meaning in this context, so n=6 is the solution to the equation.
The woman bought 6 items.
_____
Check
When the woman bought 6 items for $120, she paid $120/6 = $20 for each of them. If she bought 6+24 = 30 items for the same money, she would pay $120/30 = $4 for each item. That amount, $4, is $16 less than the $20 she paid for each item.
Answer : The amount of margarine needed is 1 kg.
Step-by-step explanation :
First we have to convert volume of syrup from mL to L.
Conversion used:
1 L = 1000 mL
or, 1 mL = 0.001 L
So, 225 mL = 0.225 L
Now we have to calculate the amount of margarine needed.
As, 0.225 L of syrup needed 150 g of margarine
So, 1.8 L of syrup needed 
of margarine
Amount of margarine needed = 1000 g = 1 kg (1 kg = 1000 g)
Therefore, the amount of margarine needed is 1 kg.
