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3 years ago

13

Grace is making holiday cards. Each rectangular card has an area of 28 square inches and the length is 3 inches more than the wi

dth. Find the length and width of her cards.

1 answer:

melomori [17]3 years ago

3 0

Length=7
Width =4
Area = length x width

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I need this solved step by step

mars1129 [50]

4-9i÷-6i times both sides by 6i
6i(4-9i)÷6i(6i)
24i-54i²÷-36i²
24i-54(-1)÷-36(-1)
54+24i÷36 now reduce
9+4i÷6
I hope this helps!!

4 0

3 years ago

Find each rate and unit rate?

VashaNatasha [74]

-60 miles per hour
-12 customers per day
-2.5 meters per second
-$1.59 per pound

You divide the first number by the second number for all of these

7 0

2 years ago

3(2x + 11) and (3x + 15)(2)

algol [13]

Answer:

3(2x+11)= 6x+33 and (3x+15)(2) = 6x+30

Step-by-step explanation:

Use distributive property to multiply the outside factor to each factor inside the parenthesis.

3(2x+11)

(3*2x)+(3*11)

6x+33

3 0

3 years ago

Mr. Jackson filled up his 15-gallon gas tank for $37.50. What was the price 10

abruzzese [7]

Answer:

$Unit Price =\$2.5 \:per\: gallon$

Step-by-step explanation:

15 Gallon of Gas costs $37.50

To determine the Unit Price, we divide the Total Cost by the number of gallons of gas bought.

Unit Price

$=\dfrac{\$37.50}{15gallons}\\Unit Price =\$2.5 \:per\: gallon$

5 0

3 years ago

Read 2 more answers

Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0

2 years ago