
Solve the following using Substitution method
2x – 5y = -13
3x + 4y = 15


- To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

- Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

- Add 5y to both sides of the equation.


- Multiply
times 5y - 13.

- Substitute
for x in the other equation, 3x + 4y = 15.

- Multiply 3 times
.

- Add
to 4y.

- Add
to both sides of the equation.

- Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

- Substitute 3 for y in
. Because the resulting equation contains only one variable, you can solve for x directly.


- Add
to
by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

- The system is now solved. The value of x & y will be 1 & 3 respectively.

$18.11 because 20.75/x=100/15
<span>(120.75/x)*x=(100/15)*x - </span>we multiply both sides of the equation by x
<span>120.75=6.6666666666667*x - </span>we divide both sides of the equation by (6.6666666666667) to get x
<span>120.75/6.6666666666667=x </span>
<span>18.1125=x </span>
<span>x=18.1125</span>
Answer: God
Step-by-step explanation: LORD HAVE MERCY
Answer: £122.4
Step-by-step explanation:
Given
The rate of interest is 4%
The principal invested is £1500
the time period is 2 years
Compound interest is given by

put values
![C.I.=1500(1+0.04)^2-1500\\C.I.=1500[1.04^2-1]\\C.I.=1500[1.0816-1]\\C.I.=1500\times 0.0816\\C.I.=122.4](https://tex.z-dn.net/?f=C.I.%3D1500%281%2B0.04%29%5E2-1500%5C%5CC.I.%3D1500%5B1.04%5E2-1%5D%5C%5CC.I.%3D1500%5B1.0816-1%5D%5C%5CC.I.%3D1500%5Ctimes%200.0816%5C%5CC.I.%3D122.4)
Therefore, interest earned is £122.4
Answer:
54
Step-by-step explanation: you add 35 and 11 together then subtract 100 by the number you got to get the anwser