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Leona [35]
3 years ago
9

Please answer 3(x-1)=5x+3-2x

Mathematics
2 answers:
Ludmilka [50]3 years ago
7 0
3x-3= 3x+3
You can’t really simplify it down more
Setler [38]3 years ago
6 0
Answer: there are no solutions



Step by step: Step 1: Simplify both sides of the equation.
3
(
x
−
1
)
=
5
x
+
3
−
2
x
(
3
)
(
x
)
+
(
3
)
(
−
1
)
=
5
x
+
3
+
−
2
x
(Distribute)
3
x
+
−
3
=
5
x
+
3
+
−
2
x
3
x
−
3
=
(
5
x
+
−
2
x
)
+
(
3
)
(Combine Like Terms)
3
x
−
3
=
3
x
+
3
3
x
−
3
=
3
x
+
3
Step 2: Subtract 3x from both sides.
3
x
−
3
−
3
x
=
3
x
+
3
−
3
x
−
3
=
3
Step 3: Add 3 to both sides.
−
3
+
3
=
3
+
3
0
=
6
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7x10 to the 3rd power, write a pattern to find the value of the expression
myrzilka [38]
Scientific notation is used to express very large or very small values.
Numbers in scientific notation are written in the form of  
m × 10 to the power of n
For example:
500 is written as 5 x 10^2 where:
500 = 5 x 10 x 10

Now, let's consider 7 x 10^3:
Following the same procedure:
7 x 10^3 = 7 x 10 x 10 x 10 = 7000
The pattern can be written as:
7 x 10^3 = 7 x 10 x 10^2 
              = 70 x 10^2
              = 70 x 10 x 10^1
              = 700 x 10
              = 7000
6 0
3 years ago
Find all zeros of function and write the polynomial as a product of linear factorsX^3-x^2+9x-9
mart [117]

Answer:

\large\boxed{x=1\ \vee\ x=-3i\ \vee\ x=3i}

Step-by-step explanation:

\text{The zeros:}\\\\x^3-x^2+9x-9=0\\\\x^2(x-1)+9(x-1)=0\\\\(x-1)(x^2+9)=0\iff x-1=0\ \vee\ x^2+9=0\\\\x-1=0\qquad\text{add 1 to both sides}\\x-1+1=0+1\\\boxed{x=1}\\\\x^2+9=0\qquad\text{subtract 9 from both sides}\\x^2=-9

8 0
3 years ago
the ratio of white flour to whole wheat flower in bread recipe is 2: 3. The recipe uses 10 cups of flour. How much of each type
7nadin3 [17]
4 cups of white and 6 cups of wheat
6 0
3 years ago
What is the m∠B?<br> 28°<br> 40°<br> 102°<br> 112°
Vlad1618 [11]

Answer:

112

Step-by-step explanation:

180 - 40 - 28 = 112

4 0
2 years ago
Read 2 more answers
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
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