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3 years ago

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Brandy is making a peach pie for her grandmother for christmas. the diameter of the pie is 12 in. if three-fourths of the area o

f the pie was eaten after christmas dinner, what is the area of the pie that is leftover?

1 answer:

Mariulka [41]3 years ago

4 0

Roughly 84 square in

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PLEASE HELP ME I DONT UNDERSTAND THANK YOU!

notsponge [240]

The correct answer is -4/63

Ming could have made it positive because the 2 fractions are negative. However, because theres another negative sign, it is a negative fraction.

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3 years ago

The system of inequalities graphed here is __________. A) inconsistent. B) indeterminate. C) consistent and dependent. D) consis

kodGreya [7K]

ANSWER

A) Inconsistent

EXPLANATION

If a system of equations has at least one solution, it is said to be consistent.

If the the system has a unique solution, then it is consistent and independent.

If the the system has infinitely many solutions, then it is consistent and dependent.

If the system of equations has no solution at all, then it is said to be inconsistent.

From the graph above, the two straight lines do not intersect because they are parallel and have different y-intercepts.

Since the two lines never meets, there is no solution for the system of equations they represent.

The correct choice is A.

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3 years ago

At a miniature golf course, after every 5 th visit you receive a free beverage. After every 12 th visit you receive a free game.

Airida [17]

Answer:

60th visit

Step-by-step explanation:

60/12=5

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3 years ago

A study found that there is no direct relationship between the time that 8th-grade students spend brushing their teeth and their

Elza [17]

Answer:

c

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no correlation, because there's no direct relationship

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3 years ago

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$

When t = 0, N = 400

$400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325$

When t = 3, N = 650

$650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49$

The equation for the population becomes:

$N = 725 - 325 e^{-0.49t}$

At t = 5, the population becomes:

$N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697$

N(5) = 700 ( to the nearest 50)

6 0

3 years ago