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natta225 [31]
3 years ago
5

If a/b = 7/2, then 2a = ___ A) 4b. B) 7b. C) 14b. D) 2b.

Mathematics
2 answers:
Anestetic [448]3 years ago
8 0
If a/b = 7/2, then 2a = 7b
jeyben [28]3 years ago
8 0

Answer:

B) 7b

Step-by-step explanation:

1. Write the equation to solve

\frac{a}{b}=\frac{7}{2}

2. Solve for a:

a=\frac{7b}{2}

3. Multiply both sides by 2 to obtain the value of 2a:

2a=2*(\frac{7b}{2})

4. Solve the equation:

2a=\frac{14b}{2}

2a=7b

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7+ 30 or 31 or 28 or 29 not sure that's what ur asking for
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Find the value of x, rounded to the nearest tenth?
Stolb23 [73]

Answer:

Step-by-step explanation:

we can use the trigonometric function in a right triangle

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cos 36°= x/10  ; multiply both sides by 10

10 * cos 36° = x ; make sure your calculator mode is in degrees

8.1  = x

4 0
3 years ago
According to the U.S. Department of Education. Institute of Education Sciences, National Center for Education Statistics 1,026,0
Andreyy89

Answer:

The correct option is C) 21.1 and 0.68  

Step-by-step explanation:

Consider the provided information.

The mean composite score was 21.1 with a standard deviation of 4.8. The ACT composite score ranges from 1 to 36, with higher scores indicating greater achievement in high school.

Therefore μ = 21.1 and σ = 4.8

It is given that the sample of 50 students;

Thus, sample size ( n ) = 50

According to the central limit theorem,

\mu_{\bar x}=\mu\ and \ \sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Therefore

\mu_{\bar x}=21.1

\sigma_{\bar x}=\frac{4.8}{\sqrt{50}}

\sigma_{\bar x}=0.68

Hence, the correct option is C) 21.1 and 0.68

7 0
3 years ago
Suppose your boss wants you to obtain a sample to estimate a population mean. Based on previous analyses, you estimate that 49 i
VashaNatasha [74]

Answer:

the minimum sample size n = 11.03

Step-by-step explanation:

Given that:

approximate value of the population standard deviation \sigma = 49

level of significance ∝ = 0.01

population mean = 38

the minimum sample size n = ?

The minimum sample size required can be determined by calculating the margin of error which can be re[resented by the equation ;

Margin of error = Z_{ \alpha /2}} \times \dfrac{\sigma}{\sqrt{n}}

38 = \dfrac{2.576 \times 49}{\sqrt{n}}

\sqrt{n} = \dfrac{2.576 \times 49}{38}

\sqrt{n} = \dfrac{126.224}{38}

\sqrt{n} = 3.321684211

n= (3.321684211)^2

n ≅ 11.03

Thus; the minimum sample size n = 11.03

5 0
3 years ago
How does a digit in the ten thousand place compare to a digit in thousands place?
vichka [17]

The digit in the ten thousands place is printed slightly to the left
of the one in the thousands place.

If they are the same digit, then the value of the one on the left is
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3 0
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