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2 years ago

What adds to 9 and multiplies to -360

Mathematics

2 answers:

Korvikt [17]2 years ago

7 0

The answer is 40 cause 4 times 9 = 36 so juat add the 0 to 4 and it makes it 40 times 9 ='360

Lynna [10]2 years ago

5 0

The answer is 24 and -15.
24 x -15 = -360
24 + (-15) = 9

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2. A teacher asked his class of 20 students, "What is your age? Their responses are shown in the dot plot below.

Karolina [17]

Answer:

Yes, average does represent the centre of this data.

Average = 15.9

Step-by-step explanation:

As this question is not complete and not correctly written. Let's try to find an answer for this question.

Total number of Students = 20 = n

and we are given this data:

14, 15, 17, 18, 16.

which is just five entries and total number of students are 20. 15 entries are missing in this questions. So, let's add our own values into this question.

New set of entries for 20 students.

1. 14

2. 15

3. 17

4. 18

5. 16

6. 19

7. 17

8. 16

9. 17

10. 17

11. 15

12. 20

13. 14

14. 17

15. 18

16. 19

17. 13

18. 20

19. 17

20. 16

So, let's calculate the average of these numbers.

Average = Sum of all entries/ Total number of entries.

Average = 318/20

Average = 15.9

So, the average age of all the students of class is 15.9.

Let's calculate median:

For median , data must be arranged in a order from least to greatest number. Median is a number from that data which is at half way. In case of odd numbers, it is easy to identify median because there is only one number. and in case of even numbers, median is the average of the two middle numbers. So, here we have even numbers and median is the average of two middle numbers = 17 + 17/2 = 17

Median = 17

Yes, average does represent the centre of this data.

8 0

2 years ago

Read 2 more answers

I have no idea what this means

Natali [406]

The answer is boxed in. follow the arrows.

7 0

2 years ago

A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

Suppose a team of doctors wanted to study the effect of different types of exercise on reducing body fat percentage in adult men

Inessa05 [86]

Answer:

A. The F statistic increases as the differences among the sample means for the exercise groups increase.

C. The F statistic has 3 degrees of freedom in the numerator and 35 degrees of freedom in the denominator.

F. The F statistic is 9.2242.

Step-by-step explanation:

Given that

Observations Samples Total

40-49 10 11 9 9 39

The degrees of freedom is given by

For numerator= k-1 = 4-1=3

For denominator= n-k= 39-4= 35

F statistic is given by

F= MS between/ MS within

=11.632991 / 1.261143 = 9.2242

Where

Mean Square Between = MS between = 11.632991

Mean Square Within = MS within = 1.261143

Hence the correct choices are A, C and F

A. The F statistic increases as the differences among the sample means for the exercise groups increase.

C. The F statistic has 3 degrees of freedom in the numerator and 35 degrees of freedom in the denominator.

F. The F statistic is 9.2242.

Suppose we have

Mean Square Between = MS between = 18.632991

Mean Square Within = MS within = 1.261143

Then F statistic would be = 14.77468 > 9.2242

which tells that The F statistic increases as the differences among the sample means for the exercise groups increase.

3 0

3 years ago

If a figure is translated 5 units down and 3 units right, how do you represent it algebraically

qwelly [4]

Answer

(x+3) -5

Step-by-step explanation:

plug the values into the parent transformation equation to its rightful places

6 0

2 years ago