Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5
Step-by-step explanation:
Since x=months,
50x=y
Where x is the number of months times the monthly charge. Y is just the output, or end value.
I hope this helps!
~kaikers
the upside down T is always perpendicular so the answer is b. :)
The graph increases untill day 4(slope= positive) and then is stays constant(slope=0). Starting at day 8 the slope changes to be negative
Answer:From the 8th day to the 10th day
Hope this helps:)
Step-by-step explanation:
We must realise that the image of the quadratic curve shown is not showing the full curve. Instead it extends further out.
For all quadratic curves, the domain is all x-values.
We see here that this quadratic curve has an absolute minimum at y = -4 and the curve stretches towards positive infinity.
Hence the range is y >= 4.
The correct answers are the 1st and 5th options.