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Gnesinka [82]
4 years ago
15

What error did Mr. Sanders likely make, and what is the actual fraction of students who have

Mathematics
1 answer:
kiruha [24]4 years ago
4 0

Answer: (1st box) = 6 (2nd box) = 2 (3rd box) = 2/3

Step-by-step explanation:

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The difference of four and a number t.
puteri [66]

Answer:

4t

Step-by-step explanation:

I know it

6 0
3 years ago
Help me please........ now
Bad White [126]
The answer would be 33
6 0
3 years ago
Read 2 more answers
Determine which of the lines, if any, are parallel or perpendicular. Explain.
pishuonlain [190]

Answer:

See below

Step-by-step explanation:

Let's rewrite all three equations is standard slope-intercept format of y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).

Line a: -x+2y=3

                 2y = x + 3

                  y = (1/2)x + 3

Line b: -6x=3y-1

             -3y = 6x - 1

               y = -2x + (1/3)

Line c: 4x-8y=5

              -8y = -4x + 5

                y = (1/2)x - (5/8)

Parallel lines have the same slope (m).  Perpendicular lines have slopes that are the negative inverse (-1/m)of each other.

Slopes, m, for the lines are;

  • a)  (1/2)
  • b)  -2
  • c)  (1/2)

The negative inverse of (1/2) is -2.

Lines a and c are parallel (same slope)

Line b is perpendicular since it's slope is the negative inverse of both a and b (-1/(1/2)) = -2

8 0
3 years ago
What is the pH of a buffer that is 0.6 M HF and 0.2 M NaF? The Ka of HF is 6.8 Ã 10â4. What is the pH of a buffer that is:______
ollegr [7]

Answer:

The correct option is  d

Step-by-step explanation:

From the question we are told that

   The concentration of  HF  is  [HF] =  0.6 M

   The concentration of  NaF  is  [NaF ] =  0.2 M

   The Ka of  HF  is  K_a  =  6.8 *10^{-4} \

Generally HF(Hydrogen fluoride )  is ionized as follows  

      HF_{(aq)} + H_2 O _{(l)}   \rightleftharpoons  H_3O^+ _{(aq) } + F^- _{(aq)}  

Generally NaF(Sodium fluoride )  is ionized as follows  

       NaF_{(aq)} + H_2 O _{(l)}   \rightleftharpoons  Na^+ _{(aq) } + F^- _{(aq)}  

Generally the from Henderson-Hasselbalch equation the pH of the buffer is mathematically represented as

       pH  =  pKa  + log [\frac{[NaF ]}{HF} ]

=>     pH  =  -log(K_a)  + log [\frac{[NaF ]}{HF} ]

=>     pH  =  -log(6.8 *10^{-4})  + log [\frac{[0.2 ]}{0.6} ]

=>    pH  =  2.69

5 0
3 years ago
What is the<br>probability of<br>picking a black card<br>from a standard<br>deck?​
Leya [2.2K]

Answer:     6/52

Step-by-step explanation:

7 0
4 years ago
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