Answer:
4t
Step-by-step explanation:
I know it
Answer:
See below
Step-by-step explanation:
Let's rewrite all three equations is standard slope-intercept format of y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).
Line a: -x+2y=3
2y = x + 3
y = (1/2)x + 3
Line b: -6x=3y-1
-3y = 6x - 1
y = -2x + (1/3)
Line c: 4x-8y=5
-8y = -4x + 5
y = (1/2)x - (5/8)
Parallel lines have the same slope (m). Perpendicular lines have slopes that are the negative inverse (-1/m)of each other.
Slopes, m, for the lines are;
The negative inverse of (1/2) is -2.
Lines a and c are parallel (same slope)
Line b is perpendicular since it's slope is the negative inverse of both a and b (-1/(1/2)) = -2
Answer:
The correct option is d
Step-by-step explanation:
From the question we are told that
The concentration of HF is [HF] = 0.6 M
The concentration of NaF is ![[NaF ] = 0.2 M](https://tex.z-dn.net/?f=%5BNaF%20%5D%20%3D%20%200.2%20M)
The Ka of HF is
Generally HF(Hydrogen fluoride ) is ionized as follows
Generally NaF(Sodium fluoride ) is ionized as follows
Generally the from Henderson-Hasselbalch equation the pH of the buffer is mathematically represented as
![pH = pKa + log [\frac{[NaF ]}{HF} ]](https://tex.z-dn.net/?f=pH%20%20%3D%20%20pKa%20%20%2B%20log%20%5B%5Cfrac%7B%5BNaF%20%5D%7D%7BHF%7D%20%5D)
=> ![pH = -log(K_a) + log [\frac{[NaF ]}{HF} ]](https://tex.z-dn.net/?f=pH%20%20%3D%20%20-log%28K_a%29%20%20%2B%20log%20%5B%5Cfrac%7B%5BNaF%20%5D%7D%7BHF%7D%20%5D)
=> ![pH = -log(6.8 *10^{-4}) + log [\frac{[0.2 ]}{0.6} ]](https://tex.z-dn.net/?f=pH%20%20%3D%20%20-log%286.8%20%2A10%5E%7B-4%7D%29%20%20%2B%20log%20%5B%5Cfrac%7B%5B0.2%20%5D%7D%7B0.6%7D%20%5D)
=> 
Answer: 6/52
Step-by-step explanation: