Order from least to greatest: -0.33, 0.25,-1/2,-0.17
2 answers:
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Total number of balls = 50
Balls numbered as multiple of 10 = 5
Balls with red dot on them = 6
Balls numbered as multiple of 10 and having red dot on them = 1 (i.e. Ball with number 40 on it)
Probability of Ball being numbered as multiple of 10 = P(T) = 5/50 = 1/10
Probability of Ball being marked by the dot = P(D) = 6/50 = 3/25
Probability of Ball being numbered as multiple of 10 and having a red dot on it = P (T ∩ D) = 1/50
The "or" ,"union" of two events can be expressed as:
P(T ∪ D) = P(T) + P(D) - P (T ∩ D)
Using the values, we get:
P(T ∪ D) =
Thus, the probability that the ball is numbered with a multiple of 10 or has a red dot is 1/5 or 0.2
Balls numbered as multiple of 10 = 5
Balls with red dot on them = 6
Balls numbered as multiple of 10 and having red dot on them = 1 (i.e. Ball with number 40 on it)
Probability of Ball being numbered as multiple of 10 = P(T) = 5/50 = 1/10
Probability of Ball being marked by the dot = P(D) = 6/50 = 3/25
Probability of Ball being numbered as multiple of 10 and having a red dot on it = P (T ∩ D) = 1/50
The "or" ,"union" of two events can be expressed as:
P(T ∪ D) = P(T) + P(D) - P (T ∩ D)
Using the values, we get:
P(T ∪ D) =
Thus, the probability that the ball is numbered with a multiple of 10 or has a red dot is 1/5 or 0.2
Answer:
B
Step-by-step explanation:
The red graph is a horizontal translation of 5 units left, followed by a reflection in the x- axis, of the black graph.
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then shift to the left of a units
• If a < 0 then shift to the right of a units
Here the graph is shifted 5 units to the left, thus
f(x) → f(x + 5)
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
Note the y- coordinate of the image is the negative of the original
Note that = - y, thus
The equation of the red graph is
= f(x + 5) → B