Answer:
2a + 30
Step-by-step explanation:
break it down so it is 4(a+5)
then work out -2(a-5)
so 4 x a then 4 x 5 which gives 4a + 20
then -2 x a then -2 x -5 which gives -2a + 10
then when you have 4a + 20 -2a + 10
do 4a - 2a which is 2a
do 20 + 10 which is 30
so the answer comes to 2a + 30
if anything doesnt seem right just comment and i will correct
hope this helps :)
Answer:-46
Step-by-step explanation: just took test
Answer:
Idk
Step-by-step explanation:idk
Answer:
Point slope is ( Y+4) = 1/2(x+3)
Slope intercept is Y = 1/2(x) -5/2
Step-by-step explanation:
For the point slope form.
Given the point as (-3,-4)
And the gradient m = 1/2
Point slope form is
(Y - y1) = m(x-x1)
So
X1 = -3
Y1 = -4
(Y - y1) = m(x-x1)
(Y - (-4)) = 1/2(x -(-3))
( Y+4) = 1/2(x+3)
For the slopes intercept form
Y = mx + c
We can continue from where the point slope form stopped.
( Y+4) = 1/2(x+3)
2(y+4)= x+3
2y + 8 = x+3
2y = x+3-8
2y = x-5
Y = x/2 - 5/2
Y = 1/2(x) -5/2
Where -5/2 = c
1/2 = m
Answer:
Y= 2e^(5t)
Step-by-step explanation:
Taking Laplace of the given differential equation:
s^2+3s-10=0
s^2+5s-2s-10=0
s(s+5)-2(s+5) =0
(s-2) (s+5) =0
s=2, s=-5
Hence, the general solution will be:
Y=Ae^(-2t)+ Be^(5t)………………………………(D)
Put t = 0 in equation (D)
Y (0) =A+B
2 =A+B……………………………………… (i)
Now take derivative of (D) with respect to "t", we get:
Y=-2Ae^(-2t)+5Be^(5t) ....................... (E)
Put t = 0 in equation (E) we get:
Y’ (0) = -2A+5B
10 = -2A+5B ……………………………………(ii)
2(i) + (ii) =>
2A+2B=4 .....................(iii)
-2A+5B=10 .................(iv)
Solving (iii) and (iv)
7B=14
B=2
Now put B=2 in (i)
A=2-2
A=0
By putting the values of A and B in equation (D)
Y= 2e^(5t)
