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AURORKA [14]
3 years ago
5

What’s the mean I’m really dumb and can’t do it x

Mathematics
1 answer:
Julli [10]3 years ago
6 0

Multiply the values across the rows. So you'll multiply each mark with its corresponding frequency

6*5 = 30

7*4 = 28

8*7 = 56

9*10 = 90

10*4 = 40

Then add up those results

30+28+56+90+40 = 244

Finally, you divide by 30 since this is the total number of scores (add up everything in the second column of the original table to get 30)

So we end up with the mean being 244/30 = 8.133 approximately

Round that value however you need to.

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Bingel [31]

the answer is 27.54

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3 years ago
karen is 3 yrs younger than floyd. floyd is 2 years older than maria. marias age is the smallest two-digit number. how old are t
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Answer:

Maria is 10, Floyd is 8, and Karen is 5.

Step-by-step explanation:

Having said that Maria's age was the smallest two-digit number, that's ten. (10). If Floyd is 2 years younger then 10-2=8. Karen is 3 years younger, so she would be 8-3=5.

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PLZ HELP ASAP SOLVE SIMMILAR TRIANGLES (BASIC)
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<span>By similarity of triangles we have the following relationship:</span>

<span> (x) / (6) = (18) / (9)</span>

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<span> (x) / (6) = 2</span>

<span> Clearing the value of x we have:</span>

<span><span> x = 6 * 2</span></span>

<span><span> X = 12</span></span>

<span><span> Answer:</span></span>

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<span><span> <span>X = 12</span></span>
</span>

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4 years ago
A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

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