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Over [174]
3 years ago
15

The number line below represents which combined inequality? number line with a closed circle on -4, shading to the left and a cl

osed circle on 3, shading to the right x greater than or equal to -4 and x less than or greater to 3 x greater than or equal to -4 or x less than or greater to 3 x less than or greater to -4 and x greater than or equal to 3 x less than or greater to -4 or x greater than or equal to 3
Mathematics
2 answers:
Elena-2011 [213]3 years ago
6 0
It is stated that their are closed circles on -4 and 3. This means, both -4 and 3 are also included in the interval.

The following regions are included in the range:

a) -4 
b) Numbers between -4 and 3
c) 3
d) Numbers greater than 3

So, the number line represents:
x greater than or equal to -4 and x less than or greater to 3.

Therefore, the first option gives the correct combined inequality. 
Deffense [45]3 years ago
4 0
<h2>Answer:</h2>

The combined inequality that is represented by the number line is:

      x less than or equal to -4 or x greater than or equal to 3

<h2>Step-by-step explanation:</h2>
  • Number line with a closed circle on -4, shading to the left .

This means that the inequality that is satisfied is:

                      x ≤ -4

Since, shaded region to left means that all the values less than that number are covered.

Also, closed circle at a number means that that number is also included in the range and hence, the inequality will be a inequality with a equal sign.

  • closed circle on 3, shading to the right

This means that the inequality is:

                     x ≥ 3

( Since, the shading is to the right this means that all the values greater than that number is covered.

Also, closed circle at that point means that the inequality will be a inequality with a equal sign)

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What is the equation of the coordinate A and B if they are (4,7), (6,3) respectively. What is the equation of the straight line.
Nesterboy [21]

Answer: y+2x=15

Step-by-step explanation:

Given

Two points A and B are (4,7) and (6,3) respectively

Using two-point form

\Rightarrow \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}

Putting values

\Rightarrow \dfrac{y-7}{x-4}=\dfrac{3-7}{6-4}\\\\\Rightarrow \dfrac{y-7}{x-4}=\dfrac{-4}{2}=-2\\\\\Rightarrow y-7=-2x+8\\\\\Rightarrow y+2x=15

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3 years ago
Find the straight time pay if you earn $7.90 per hour and worked 37 hours.
S_A_V [24]

Answer: $292.30

Step-by-step explanation:

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3 years ago
What are the domain and range of the function f(x) = 3x + 5?
Sidana [21]

Answer:

B

Step-by-step explanation:

Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis. This function 3^x+5 has been moved up 5 units so its asymptote is at y=5. This means the function never goes below 5 in its y-values.

The x values are not affected and all are in the function. This is the domain. So the domain is (-∞, ∞).

The y values are affected and are y > 5. This is the range and it is written

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7 0
3 years ago
Read 2 more answers
Which point satisfies the system of equations y=3x-2 and y=-2x+3?<br><br>​
horrorfan [7]

Answer:

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3 0
3 years ago
How to solve Y^2-8y-16
aleksley [76]
You can't solve it because it isn't equal anything
but we can factor

since the quadratic coefient (number in front of y^2 term) is 1

we can do this
for ax^2+bx+c
when a=1
what 2 numbers multiply to c and add to b



what 2 numbers multiply to -16 and add to -8
no numbers
if you had y^2-8y+16 then that would be (x-4)(x-4)

but no

ok, so we need to complete the squaer


so


y^2-8y-16
take 1/2 of linear coefient and square it
-8/2=-4, -4^1=16
add negative and poisitve to it
y^2-8y+16-16-16
factor
(y-4)^2-16-16
(y-4)^2-32
then we can force factor again
remember difference of 2 perfect square
a^2-b^2=(a+b)(a-b)
√32=4√2
so
(y-4)^2-(4√2)^2=(y-4+4√2)(y-4-4√2)

the factore form would be (y-4+4√2)(y-4-4√2)
not equal to anything tho so we can't solve
8 0
2 years ago
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