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qaws [65]
3 years ago
6

Geometry help anyone!!

Mathematics
1 answer:
Monica [59]3 years ago
6 0

Check the picture below.

\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ h = 6\\ r=3 \end{cases}\implies V=\pi (3)^2(6)\implies \stackrel{in^3}{V=54\pi}

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Water flows on the Amazon river near the cachoeira de Santuario waterfalls at a velocity 75 meters per second. If a low height r
zysi [14]

Answer:

7.5 MW

Step-by-step explanation:

The power generated from a falling water is a function of its height and volume. The power generated an be calculated using the formula:

Power (P) = Density(ρ) * volume flow rate(Q) * acceleration due to gravity(g) * height(h)

P = ρQgh

But Qh = Velocity(v) * volume(V).

Hence power = ρvgV

Given that ρ of water = 1000 kg/m³, v = 75 m/s, V = 10 m³, g = 10 m/s². Substituting:

P = ρvgV = 1000 * 75 * 10 * 10 = 7500000 W

P = 7.5 MW

4 0
3 years ago
What is 12/60 expressed in lowest terms<br> 1/4<br> 1/8<br> 1/6<br> 1/5
Ahat [919]
1/5 because you divide them both equally by 2 and then by 2 and then by 3 and you get 1 and 5. :)
8 0
3 years ago
Read 2 more answers
Jared has $100.00 to spend on clothes at the mall. He purchases 5 shirts that cost $10.50 each, a pair of pants that cost $31.99
Verizon [17]
100$ - 52.5 = 47.5 ( 31.99 - 7.49) = 24.5 Answer is 24.5. Jared has 24.5$ remanding or 24.05$. Hope this helped.
8 0
3 years ago
Read 2 more answers
Please help will give points!!!!
slavikrds [6]

Answer:

Between 1 and 6

3 0
4 years ago
Evaluate the function <br><br> f(x)=−4x^2+6x−4 <br><br> Find f(5)
Tamiku [17]

Hey there!

1. How to find f(5)?

  • To find f(5) - simply substitute x = 5 in the function. f(5) means the value of f(x) at x = 5.

2. Substitution and Evaluate

\large{f(5) =  - 4( {5})^{2}  + 6(5) - 4}

Remember to follow the PEMDAS/BODMAS rules! Exponent comes before multiplication.

\large{f(5) =  - 4(25) + 30 - 4} \\  \large{f(5) =  - 100 + 30 - 4} \\  \large{f(5) =  - 74}

3. Final Answer

  • f(5) = -74

If you have any questions regarding the question or my answer, feel free to ask!

8 0
3 years ago
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