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qaws [65]
3 years ago
6

Geometry help anyone!!

Mathematics
1 answer:
Monica [59]3 years ago
6 0

Check the picture below.

\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ h = 6\\ r=3 \end{cases}\implies V=\pi (3)^2(6)\implies \stackrel{in^3}{V=54\pi}

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

m_ {1} * m_ {2} = - 1

The given line is:

5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3

So we have:

m_ {1} = \frac {5} {2}

We find m_ {2}:m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}

So, a line perpendicular to the one given is of the form:

y = - \frac {2} {5} x + b

We substitute the given point to find "b":

-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2

Finally we have:

y = - \frac {2} {5} x-2

In point-slope form we have:

y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)

ANswer:

y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)

3 0
3 years ago
Read 2 more answers
Division 54 /7.5 plz answer this​
harkovskaia [24]

Answer:

turn the decimal into a whole number by multiplying by 10, 100 (what you do to one number you must do to the other)

multiply both by 10 it then becomes

540/75 = 7.2

it's easier to divide whole numbers and is the same answer as 54/7.5

6 0
3 years ago
What is the answer to X^2-61=20
Reika [66]
X^2 -61 =20
X^2= 81x =9 x=-9
7 0
3 years ago
Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What
777dan777 [17]

Answer:

B) \frac{3}{4} x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

                               = 40 units

Dilating KMPT by a scale factor of \frac{3}{4} would create K'M'P'T' of dimensions; \frac{3}{4} × 12 units by \frac{3}{4} × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

                                  = 2(9 + 6)

                                  = 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be  \frac{3}{4} × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

         perimeter of K'M'P'T' = \frac{3}{4} * x units

                                            = \frac{3}{4}x units

6 0
3 years ago
What is the area of the triangle plz help
JulsSmile [24]
3x4x1/2= 6inches Multiply the base by the height and after multiply by one half
3 0
3 years ago
Read 2 more answers
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