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mestny [16]
2 years ago
14

I don't understand how it gets the result

8b_{2}" align="absmiddle" class="latex-formula"> and b_{2}^{2} in the fourth equation.

Mathematics
1 answer:
Maksim231197 [3]2 years ago
7 0

Answer + Step-by-step explanation:

<u><em>your question is about equation 4</em></u> :

b_{1}=14-b_{2}

Then

\left( b_{1}\right)^{2}  =\left( 14-b_{2}\right)^{2}   \  \text{(this is a special product )}

Then

\left( b_{1}\right)^{2}  =14^{2}-2\times 14 \times b_{2}+ (b_2)^2

Then

\left( b_{1}\right)^{2}  =196-28 b_{2}+ (b_2)^2

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Answer:

7.50x=185

Step-by-step explanation:

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3 years ago
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A circle has a diameter of 14cm. What's the circumfrence?
vesna_86 [32]
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7 0
3 years ago
6x - 2y = 5
laiz [17]

Answer:

The given system has NO SOLUTION.

Step-by-step explanation:

Here, the given system of equation is:

6 x -  2 y = 5     .......... (1)

3 x  - y = 10          .... (2)

Multiply equation 2 with (-2), we get:

3 x  - y = 10     ( x -2)

⇒  - 6 x + 2 y = - 20

Now, ADD this to equation (1) , we get:

6 x - 2 y  - 6 x + 2 y  = 5 - 20

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3 years ago
Solve for X.<br><br> 2<br> 5<br> 25<br> 75
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Step-by-step explanation:

x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2

First step is to put all the same ones together

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7 0
3 years ago
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