Answer:

Step-by-step explanation:
Given:
Interval, [0, 4]
Required:
Average range of change over [0, 4]
SOLUTION:
Find f(0) and f(4) from the graph:
(when x = 0, y = 0)
(when x = 4, y = 3)
Average rate of change = 
Where,


Plug in the values into the formula for average rate of change.


Average rate of change 
Ok, so it seems to be the square root of the cube root of 2
we just convert to exponential
remember

and
![\sqrt[n]{x^m} =x^ \frac{m}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%3Dx%5E%20%5Cfrac%7Bm%7D%7Bn%7D%20)
therfor
![\sqrt{ \sqrt[3]{2} }= \sqrt{2^ \frac{1}{3} } =( 2^ \frac{1}{3})^ \frac{1}{2} =2^ \frac{1}{6}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Csqrt%5B3%5D%7B2%7D%20%7D%3D%20%5Csqrt%7B2%5E%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%28%202%5E%20%5Cfrac%7B1%7D%7B3%7D%29%5E%20%5Cfrac%7B1%7D%7B2%7D%20%3D2%5E%20%5Cfrac%7B1%7D%7B6%7D%20%20)
last choice is correct
One metric ton is equal to 1000 Kilograms
B. (2,20] is the correct answer