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2 years ago

What is the volume of the right rectangular prism?

1 answer:

3 0

I saw the image that should have been included in this problem.

It was a rectangular prism. It can also be identified as a right prism because its bases are aligned one directly above the other and its lateral faces are rectangular.

The image has the following measurements:
length = 7 inches
width = 5 inches
height = 4 inches

volume = length * width * height
v = 7 in * 5 in * 4 in
v = 140 in³ Choice B i believe.

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The height of a triangle is 4 m less than its base. The area of the triangle is 48 m^2.

masya89 [10]

Answer:

Step-by-step explanation:

Let x = base measurement; then height = (x-4).

A = ½•base•height 48 = ½x(x-4

4 0

2 years ago

. In a triangle, the second angle measures twice the first, and the third

IRISSAK [1]

Answer:

First angle = x = 35°

Second angle = 2x = 2(35) = 70°

Third angle = 2x+5 = 70 + 5 = 75°

Step-by-step explanation:

Given : 

The second angle measures twice the first, and the third angle measures 5 more than the second.

Sum of angles = 180°

Solution : 

Let the first angle be x

According to the given question :

Second angles = 2x

Third angle = 2x + 5

we know that Sum of angles = 180°

Solving x value :

x + 2x + (2x+5) = 180°

5x + 5 = 180

5x = 180 - 5

5x = 175

x = 175/5

x = 35

Finding the measure of each angle : 

First angle = x = 35°

Second angle = 2x = 2(35) = 70°

Third angle = 2x+5 = 70 + 5 = 75

3 0

2 years ago

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Shalnov [3]

Answer:

The solution is correct.

Step-by-step explanation:

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8 0

2 years ago

Factor completely 4(x+1)^2/3 + 12(x+1)^-1/3

wolverine [178]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\
-------------------------------\\\\
%4(x+1)^2/3 + 12(x+1)^-1/3
4(x+1)^{\frac{2}{3}}+12(x+1)^{-\frac{1}{3}}\implies 4(x+1)^{\frac{2}{3}}+12\cfrac{1}{(x+1)^{\frac{1}{3}}}
\\\\\\$

$\bf 4(x+1)^{\frac{2}{3}}+\cfrac{12}{(x+1)^{\frac{1}{3}}}\impliedby \textit{so, our LCD is }(x+1)^{\frac{1}{3}}
\\\\\\
\cfrac{4(x+1)^{\frac{2}{3}}\cdot (x+1)^{\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)^{\frac{2}{3}+\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4(x+1)^{\frac{3}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4x+4+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4x+16}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+4)}{\sqrt[3]{x+1}}$

3 0

3 years ago

Read 2 more answers

Tyler completely filled the Box shown below with unit cubes with no gaps or overlaps even counted the number of Cubes that he us

Mamont248 [21]

Question:

The options are

A. area

B. height

C. volume

D. perimeter

Answer:

The correct option is;

C. volume

Step-by-step explanation:

Here we note that the size of the unit cube is 1 cubic unit

When the box is filled with the unit cubes the total number of unit cubes represent the volume capacity of the box into which the number of nit cubes are placed.

The volume is a quantity that is also represented by the product of the length, width and height dimensions of the cube.

5 0

2 years ago