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boyakko [2]
3 years ago
5

At a restaurant, Brandy paid twice as much as Katie, and Katie paid $3 more than Stephanie. If the total combined amount they pa

id was $56, how much did Katie pay? A. $12.50 B. $13.00 C. $14.00 D. $14.75
I need the answer ASAP
Mathematics
1 answer:
gregori [183]3 years ago
4 0
Let the amount that Brandy paid be b, the amount that Katie paid be k, and the amount that Stephanie paid be s.

b=2k
s=k+3
b+s+k=56

Substituting and doing the equation only in terms of k, we get:

2k+(k+3)+k=56
4k+3=56
4k=53
k=13.25
Katie paid $13.25.
Hope this helps!
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Osvoldo has a goal of getting at least 30% of his grams of carbohydrates each day from whole grains. Today, he ate 220 grams of
pochemuha

Answer:

Answer: Osvoldo did not meet his goal.

Step-by-step explanation:

Total carbohydrate ate by Osvoldo = 220 g

carbohydrate from grains = 55 g

Percentage of carbohydrate of grain is

\begin{gathered}=\dfrac{\text { carbohydrate taken from grains}}{\text {Total carbohydrate}} \times 100\\\\= \dfrac{55}{220} \times 100= 25 \%\end{gathered}

=

Total carbohydrate

carbohydrate taken from grains

×100

=

220

55

×100=25%

Goal of getting carbohydrate from grains = at least 30%

but he ate only 25% of carbohydrate

Hence, Osvoldo did not meet his goal as he ate less carbohydrate than his goal.

8 0
3 years ago
0-6
dybincka [34]
<h3>Given :-</h3>
  • Pranav ran 20.3 km more than Branda

  • Pravin ran 38.6 km

\\  \\

To find :

  • No. of kilometers did Brenda run.

\\  \\

<h3>Let :</h3>

  • No. of kilometers ran by Brenda be x.

\\  \\

<h3>Solution:</h3>

\\  \\

Equation formed:-

\\  \\

Total distance covered by Pravan = More distance covered by Pravan + distance covered by Brenda.

Therefore:-

\\  \\

\leadsto \sf38.6 = 20.3 + x

Write the equation

\\  \\

\leadsto \sf38.6 - 20.3 =x

When we transfer 20.3 to left side the positive sign (+) will change into negative sign (–)

\\  \\

\leadsto \sf x = 38.6 - 20.3

Arrange the equation because x is always represented at left side.

\\  \\

\leadsto \boxed {\pmb{\sf x = 18.3}}\star

After subtracting 38.6 with 20.3 we will get result as 18.3 .

\\  \\

\therefore \red{ \underline{  \pmb{\frak{Distance  ~ covered ~by ~Brenda~ is ~equal ~to~18.3~kilometers}}}}

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3 years ago
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