The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years, is 540 grams.
<h3>What is half-life?</h3>
This can be defined as the time taken for half the amount of a radioactive substance to decay.
To calculate the amount of cesium left after 120 years, we use the formua below.
Formula:
- R' = R/(
)............. Equation 1
Where:
- R = Original amount of Cesium
- R' = New amount of cesium
- T = Total time
- t = Half-life
From the question,
Given:
- R = 8640
- T = 120 years
- t = 30 years
Substitute these values into equation 1
- R' = 8640/(
) - R' = 8640/

- R' = 8640/16
- R' = 540 grams.
Hence, The mass of cesium left afer 120 years is 540 grams.
Learn more about half-life here: brainly.com/question/25750315
Answer:
96 units^2
Step-by-step explanation:
area of a triangle A=bxh/2
substitute b with 8 and h with 24
A=8x24/2
multiply
A=193/2
the divide
A=96
Okay so 3n- 4 =?
We have to insert the -2 into the problem where n is creating,
3(-2)-4=?
Then we simplify,
-6-4=?
Lastly the answer,
-10
Answer:
<h2><em><u>
A to C = 25
</u></em></h2><h2><em><u>
A to B = 13
</u></em></h2><h2><em><u>
C to B = 37
</u></em></h2><h2><em><u>
</u></em></h2>
Step-by-Step Explanation:
<em><u>Perimeter</u></em> = 75
<em><u>Sides:</u></em>
2x + 3
3x + 4
2x - 9
<h2 /><h2><em><u>
1. Equal the sides added together to the perimeter</u></em></h2>
75 = 2x + 3 + 3x + 4 + 2x - 9
<h2><em><u>
2. Simplify Like terms</u></em></h2>
2x + 3 + 3x + 4 + 2x - 9 = 7x - 2
<h2><em><u>
3. Place the equation back together</u></em></h2>
75 = 7x - 2
<h2><em><u>
4. Isolate the variables and numbers</u></em></h2>
75 = 7x - 2
+2 +2
77 = 7x
<h2><em><u>
5. Simplify the equation</u></em></h2>
77 = 7x
/7 /7
<h2><em><u>
11 = x
</u></em></h2>
<h2><em><u>
6. Substitute the value of x into the side lengths.</u></em></h2>
2x + 3 = 2(11) + 3 = 22 + 3 = <em><u>25</u></em>
3x + 4 = 3(11) + 4 = 33 + 4 = <em><u>37</u></em>
2x - 9 = 2(11) - 9 = 22 - 9 = <em><u>13</u></em>
Answer:
35. 
36. 
Step-by-step explanation:
Question 35:
Given:


Plug in 2 for
and simplify. This gives,

Therefore, term 2 is 16.
Question 36:
Given:


Plug in 2 for
and simplify. This gives,

Therefore, term 2 is 77.