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nikitadnepr [17]
3 years ago
15

The circumference of a circle is 32π. What is the diameter of this circle?

Mathematics
1 answer:
lawyer [7]3 years ago
4 0
C = 2 (pi) r 

32 (pi) = c

32 (pi)= 2 (pi) r 

r= 16 

2r = d 
 d= 32

hope that helps
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Answer:

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Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

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So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

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Step-by-step explanation:

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Step-by-step explanation:

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