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Lubov Fominskaja [6]
2 years ago
14

suppose you have a dime, two pennies, and a quarter. one of the pennies was minted in 1976, and the other one was minted in 1992

. (a) assuming you choose at least one coin, how many different sets of coins can you form? different sets (b) assuming you choose at least one coin, how many different sums of money can you produce? different sums (c) explain why the answers in part (a) and part (b) are not the same. two different sets of coins have different value. two different sets of coins can have the same value. the answers in part (a) and part (b) are the same.
Mathematics
1 answer:
notsponge [240]2 years ago
3 0

The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

<h3>How to Solve Counting Problems?</h3>

A) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins. Let us label the dime as D, the penny as P, the quarter minted in 1976 as Q1 and the quarter minted in 1992 as Q2.

Now, if you choose one coin, you could choose either D, P, Q1, or Q2. This gives us 4 possible sets.

If you choose two coins, you choose the following sets of coins: DP, DQ1, DQ2, PQ1, PQ2, Q1Q2. This gives us 6 possible sets.

If you choose three coins, you could the following sets of coins: DPQ1, DPQ2, DQ1Q2, PQ1Q2. This gives us 4 possible sets.

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible set.

Therefore, the total number of different sets of coins you can form is 4 + 6 + 4 + 1 = 15 different sets of coins can be formed.

b) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins.

If you choose one coin you could choose either D, P, Q1, or Q2. However, since Q1 and Q2 give us the same sum, they are effectively the same set. This gives us 3 possible sums (ten cents, one cent, or twenty-five cents.)

If you choose two coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DP, DQ, PQ, Q1Q2. This gives us 4 possible sums (11 cents, 35 cents, 26 cents, or fifty cents.)

If you choose three coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DPQ, DQ1Q2, PQ1Q2. This gives us 3 possible sums (36 cents, 60 cents, or 51 cents).

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible sum (61 cents.)

Therefore, the total number of different sums of coins you can form is 3 + 4 + 3 + 1 = 11 different sums of money can be produced.

c) The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

Read more about Counting Problems at; brainly.com/question/13875198

#SPJ1

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andreev551 [17]

If the distance between the two twons equals 750 km, and the cars met at some point on the road then the distance of the first car added to the distance of the second car equals 750 km, like this:

d1 + d2 = 750

Where d1 is the driven distance by the first car and d2 is the driven distance by the second car.

Distance, is the product of speed and time, then we can rewrite the above equation like this:

s1×t + s2×t = 750

S1 is the speed of the first car and s2 is the speed of the second time, t is the time. We already know that the time it took the cars to meet each other equals 5 hours, then, by replacing 5 for t into the above expression, we get:

s1×5 + s2×5 = 750

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We are also told that the speed of the first car is 12 less than the speed of the second car, this means that the speed of the first car equals the speed of the second one minus twelve. Then we can formulate the following expression for the speeds of the cars:

s1 = s2 - 12

By replacing s2 - 12 for s1 into 5(s1 + s2) = 750 we get:

5(s1 + s2) = 750

5(s2 - 12 + s2) = 750

5(s2 + s2 - 12) = 750

5(2s2 - 12) = 750

By dividing both sides by 5, we get:

(2s2 - 12) = 750/5

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By adding 12 on both sides:

2s2 = 150 + 12

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Finally, by dividing by 2 on both sides:

s2 = 162/2

s2 = 81

Now that we know that the speed of the second car, equals 81, we can find the speed of the first car by means of the formula s1 = s2 - 12, then we get:

s1 = s2 - 12

s1 = 81 - 12

s1 = 69

Then, the speed of the slower car equals 69 kilometers per hour

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The conversion factor between radians and revolution as measures of angle is 2π rad is equal to 1 revolution. Converting the given angular velocity to rev/s,
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Dividing the given angle, 20 rev by the velocity,
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12w - 13 - 11w + 24 = 77

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Hi there!

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