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3 years ago

Solve for z 15z–19≥–9 or z+13≤6

Mathematics

2 answers:

babunello [35]3 years ago

5 0

Answer:

the answer is A

i hope this helps

ICE Princess25 [194]3 years ago

5 0

The answer is A! hope it helps :)

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What equation in slope intercept form represents the line that passes through the two points? (2, 5), (9, 2) Question 6 options:

Tema [17]

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})\qquad
(\stackrel{x_2}{9}~,~\stackrel{y_2}{2})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-5}{9-2}\implies \cfrac{-3}{7}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=-\cfrac{3}{7}(x-2)
\implies y-5=-\cfrac{3}{7}x+\cfrac{6}{7}
\\\\\\
y=-\cfrac{3}{7}x+\cfrac{6}{7}+5\implies y=-\cfrac{3}{7}x+\cfrac{41}{7}$

5 0

3 years ago

What is the vertex of the graph of y = 3x2 + 2x + 1?

Effectus [21]

We have that
y = 3x²<span>+ 2x + 1

step 1
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y -1= (3x²+ 2x)

step 2

Factor the leading coefficient

y -1= 3*(x²+ 2/3x)

step 3

Complete the square. Remember to balance the equation by adding the same constants to each side

y -1+(1/3)= 3*(x²+ (2/3)x+(4/36))

y-2/3=3*(x+2/6)²

the vertex is the point (-2/6, 2/3)------> (-0.33,0.67)

the answer is

(-0.33,0.67)

8 0

3 years ago

Read 2 more answers

Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round

Karo-lina-s [1.5K]

Answer:

1. D. $50\text{ units}^2$

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of base line of our triangle we will get,

$\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}$

$\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}$

$\text{Base length of triangle}=\sqrt{100+100}$

$\text{Base length of triangle}=\sqrt{200}$

$\text{Base length of triangle}=10\sqrt{2}$

Now let us find the height of triangle similarly.

$\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}$

$\text{Height of triangle}=\sqrt{(5)^2+(5)^2}$

$\text{Height of triangle}=\sqrt{25+25}$

$\text{Height of triangle}=\sqrt{50}$

$\text{Height of triangle}=5\sqrt{2}$

$\text{Area of triangle}=\frac{\text{Base*Height}}{2}$

$\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}$

$\text{Area of triangle}=\frac{50*2}{2}$

$\text{Area of triangle}=50$

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

$\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}$

$\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}$

$\text{Large side of rectangle}=\sqrt{169+169}$

$\text{Large side of rectangle}=\sqrt{338}$

$\text{Large side of rectangle}=13\sqrt{2}$

$\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}$

$\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}$

$\text{Small side of rectangle}=\sqrt{9+9}$

$\text{Small side of rectangle}=\sqrt{18}$

$\text{Small side of rectangle}=3\sqrt{2}$

$\text{Perimeter of rectangle}=2(\text{Length + Width)}$

$\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}$

$\text{Perimeter of rectangle}=2(16\sqrt{2}}$

$\text{Perimeter of rectangle}=32\sqrt{2}$

$\text{Perimeter of rectangle}=45.2548339959390416\approx 45$

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

8 0

4 years ago

Read 2 more answers

I need to know, the area of sector AOB is what fractional part of the area of circle O

sertanlavr [38]

We are given that triangle AOB

6 0

1 year ago

If four times a certain number, increased by 6 is equal to 94, what is the number?

aniked [119]

"4x + 6 = 94" is the equation among the following choices given in the question that could be used to solve the problem. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that you were looking for and it has actually come to your help.

7 0

4 years ago