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vovangra [49]
3 years ago
9

How much work is done when 0.0050 c is moved through a potential difference of 9.0 v? use w = qv?

Physics
2 answers:
quester [9]3 years ago
8 0

Answer:

0.045 APEX

Explanation:

quester [9]3 years ago
4 0

Answer:

0.045 J

Explanation:

The work done on a charge moving through a potential difference is given by

W=q\Delta V

where

W is the work done

q is the charge

\Delta V is the potential difference

In this problem, we have

q = 0.0050 C is the charge

\Delta V=9.0 V is the potential difference

Using the formula, we find the work done:

W=(0.0050 C)(9.0 V)=0.045 J

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A neutral atom of tin (Z = 50) has 69 neutrons. (a) How many protons does it have? (b) What is its mass number?
Olenka [21]

Answer:

Protons = 50

Mass number = 119

Explanation:

A neutral of tin, Sn, has a Z value of 50 and neutrons are 69.

Z is the atomic number. The atomic number is equal to number of protons or number of electrons in an atom that is neutral i.e:

Z = PROTONS = ELECTRONS

So the number of protons = 50 since Z is 50

>>>>>>>>>>>>>>>¦

The bulk of the mass of an atom is concentrated in the nucleus. To calculate mass number, we simply sum all the elementary particles in the nucleus i.e protons and neutrons. These particles are called the nucleons.

Mass number (A) = P + N

= 50 + 69

= 119

3 0
3 years ago
Which is the quickest way to accurately take your heart rate
Thepotemich [5.8K]
I would say by putting two fingers under your chin or putting two fingers on the back of your wrist, hope i helped ! :)
3 0
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When Earth and the Moon are separated by a
Wewaii [24]
     Using the Universal Gratitation Law, we have:

F= \frac{MmG}{d^2}  \\ MmG=2*10^{20}*(3.84*10^8)^2 \\ MmG=29.4912*10^36
 
     Again applying the formula in the new situation, comes:

F= \frac{MmG}{d^2} \\ F= \frac{29.4912*10^36}{(1.92*10^8)^2} \\ \boxed {F=8*10^{20}}

Number 4

If you notice any mistake in my english, please let me know, because i am not native.
6 0
4 years ago
Read 2 more answers
What is the weight of a pumpkin with a mass of 5 kg? kk
pav-90 [236]

Explanation:

actually, the question would need to give you what is the gravitational force, so let's take the average of the gravitational for me which is 10 N /kg

and the formula for finding weight is

W = mg

W = (5)(10)

W = 50 N

hope it is helpful, if not please report it so that someone else gets to try

please vote

4 0
3 years ago
A spring stretches 0.018 m when a 2.8-kg object is suspendedfrom its end. How much mass should be attached to this spring sothat
agasfer [191]

Answer:

m = 4.29 kg

Explanation:

Given that,

Mass of the object, m = 2.8 kg

Stretching in the spring, x = 0.018 m

Frequency of vibration, f = 3 Hz

Let m is the mass of the object that is attached to the spring. When it is attached the gravitational force is balanced by the force on spring. It is given by :

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{2.8\times 9.8}{0.018}

k = 1524.44 N/m

Since, \omega=\sqrt{\dfrac{k}{m}}

m=\dfrac{k}{4\pi^2 f^2}

m=\dfrac{1524.44}{4\pi^2 \times 3^2}

m = 4.29 kg

So, the mass that is attached to this spring is 4.29 kg. Hence, this is the required solution.

4 0
3 years ago
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