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faltersainse [42]
3 years ago
15

If one-third of a number, x, is greater than five less than twice the number, which of the following is true?

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

x= 15/7

Step-by-step explanation:

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Four more than 3 times a number is 31. Find that number
SpyIntel [72]

Answer:9

Step-by-step explanation: 31-4=27

27÷3=9

7 0
3 years ago
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How could you use this information to determine the erosion after 10 years? *
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Answer:

{\huge{\mathfrak{\underbrace{\pink{Answer}}}}}

.

.

<h3><em>Erosion is the geological process in which earthen materials are worn away and transported by natural forces such as wind or water. A similar process, weathering, breaks down or dissolves rock, but does not involve movement.</em></h3>

<em>.</em>

<em>.</em>

<em>u</em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

3 0
2 years ago
Item 14
dsp73

Answer:

13/21

Step-by-step explanation:

5 0
2 years ago
How many 3 digit numbers can you make using these numbers: 4,2,9 (numbers can be reapeated)
bogdanovich [222]

Answer:

You can make 27 different 3 digit numbers

Step-by-step explanation:

Since we can use 3 different numbers this means that each of the 3 digits can be one of the 3 numbers (4,2,9). This means that there are 3 different values for the first digit, 3 different values for the second digit, and 3 different values for the third digit, which mean that we can make 3 x 3 x 3 different 3 digit numbers (we took the number of possible values for each digit and multiplied them together.

3 x 3 x 3 = 27

8 0
3 years ago
In front of a store, there is a row of parking spaces. Cars park parallel to one another, with the front of each car facing the
Gelneren [198K]

The width used for the car spaces are taken as a multiples of the width of

the compact car spaces.

Correct response:

  • The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>

Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.

We have;

Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)

New space design = 16·x + 9×(a·x) = x·(16 + 9·a)

When the dimensions of the initial and new arrangement are equal, we have;

10 + 12·a = 16 + 9·a

12·a - 9·a = 16 - 10 = 6

3·a = 6

a = 6 ÷ 3 = 2

a = 2

Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;

10 + 12·a < 16 + 9·a

Which gives;

x·(10 + 12·a) < x·(16 + 9·a)

Therefore;

The initial total car park space is less than the space required for 16

compact spaces and 9 full size spaces, therefore; the store owners are

incorrect.

Learn more about writing expressions here:

brainly.com/question/551090

5 0
2 years ago
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