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stellarik [79]
3 years ago
15

A soda container holds 5 1/2 gallons of soda.how many ounces of soda does this container holds?

Mathematics
1 answer:
dusya [7]3 years ago
5 0
5\frac{1}{2}gallon=5\frac{1}{2}*4quarts=\frac{11}{2}*4quarts=22quuarts\\\\22quarts=22*32ounce=704\ ounce\\\\Solution\ is\ 5\frac{1}{2}gallon=704\ ounce.
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garri49 [273]

Answer:

the correct answer is $14.55%

6 0
3 years ago
You deposit $200 each month into an account earning 3% interest compounded monthly.
zvonat [6]

The total amount of money accrued ( principal and interest ) in 35 years is $570.78.

<h3>What is the total amount accrued?</h3>

The formula for compound interest is expressed as;

A = P( 1 + r/t )^(n×t)

Given the data in the question;

  • Principal P = $200
  • Rate r = 3% = 3/100 = 0.03
  • Compounded monthly n = 12
  • Time t = 35
  • Amount accrued in 35 years A = ?

Plug the given values into the equation above.

A = P( 1 + r/n )^(n×t)

A = 200( 1 + 0.03/12 )^(12×35)

A = 200( 1 + 0.0025 )^(420)

A = 200( 1.0025 )^(420)

A = 200( 2.85390914 )

A = $570.78

Therefore, the total amount of money accrued ( principal and interest ) in 35 years is $570.78.

Learn more about compound interest here: brainly.com/question/27128740

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7 0
1 year ago
Which expression is equivalent to 6a + 15? A. 6(a + 5) B. 3(2a + 5) C. 3(3a + 12) D. 6(a + 12) PLEASE HELP :)
makvit [3.9K]
The answer is B

A. 6(a+5)
=6a+30 not equivalent to 6a+15
B.3(2a+5)
=6a+15 is equivalent
C.3(3a+12)
=9a+36 not equivalent
D.6(a+12)
=6a+72 not equivalent

So your answer is B
4 0
3 years ago
Read 2 more answers
In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
2 years ago
Can someone help me with this worksheet? I'm trying to check my daughter's work and I'm not sure how to do this. Showing the wor
Kaylis [27]

Answer:

Step-by-step explanation:

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