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3 years ago

Which of these is correct step in constructing congruent angles?

Mathematics

1 answer:

lapo4ka [179]3 years ago

6 0

Is something missing
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3. What additional information do you need to prove AABC = ADEF by the SAS Postulate?

Elden [556K]

Answer:

∠ACB = ∠DFE

Step-by-step explanation:

In SAS postulate,

S refers to Side.

A refers to Angle.

In the triangles, △ABC and △DEF,

AC = DF ( Side )

CB = FE ( Side )

The additional information required to prove is Angle.

Angle between sides AC and CB in △ABC and Angle between sides CB and FE in △DEF respectively.

Angle between sides AC and CB is ∠ACB.

Angle between sides CB and FE is ∠DFE.

So according to SAS postulate,

∠ACB = ∠DFE

6 0

2 years ago

The formula v =sqrt 64h can be used to find the velocity, v, in feet per second, of an object that has fallen h feet. Find the v

viktelen [127]

I think first that the 64 h should be in parantheses so v=sqrt(v*h) where sqrt means square root. If it falls 75 feet, then here h is 75 ft. Then v=sqrt(64*75)=sqrt (4800)=69.282. Rounded to the nearest tenth our answer would be 69.3 ft/sec.

7 0

3 years ago

Jasmine reduced the size of a triangle to a height of 4 in. What is the new width if it was originally 12 in wide and 16 in tall

cupoosta [38]

Answer:

The new width is 3 in.

Step-by-step explanation:

We can use the ratio of w/h, the origal width and height should have the same ratio as the new width and height.

12 = x

16 4

Then solve for x:

x = 4 (12/16)

x = 3

To check:

12/16 = 3/4

3/4 = 3/4

7 0

2 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

Which of the following must be true?

Naddika [18.5K]

Answer:

B, it's the only plausible one. A is wrong because the value would be above 180°

5 0

4 years ago

Read 2 more answers