<span>At 8in to 250 feet the skyscraper converts to the following.
1.6 in/8 in x 250ft = 50 ft long
2.8in/8in x 250ft = 87.5 ft wide
11.2in/8in x 250ft = 350 ft high
You get this because every 8 in is 250 feet so you need to calculate the ratio of scale to that 8in per 250 feet.</span>
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
Step-by-step explanation:
Given data:
Circumference of the base of the cone = 24in.
Recall that circumference (in this case) is the distance round the base of the cone and from here the diameter D=12in. Radius = 6in
Surface area l = pie x radius ( slant height + radius)
= 3.142 x 6 (20 + 6)
= 3.142 x 6 (26)
= 3.142 x 156
= 490.152in^2
<span> (3a - 4)</span>²
= (3a)² - 2*3a*4 + 4²
= 9a² - 24a + 16
Answer:
$6,580
Step-by-step explanation:
