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liraira [26]
2 years ago
10

Give three examples of how scatterplots are used in the real world

Mathematics
2 answers:
Irina18 [472]2 years ago
5 0

Answer:

Scatter plots help visually illustrate relationships between two economic phenomena, such as employment and output, inflation and retail sales, and taxes and economic growth.

Step-by-step explanation:

I used a website for this, so answer this with your own words

Brut [27]2 years ago
3 0

Answer:

\huge \text{\textbf{\textit{Hello! :)} }}

  • <em>A scatterplot is a type of data chart that shows the relationship between two numerical variables. </em>

<em> Examples of how scatterplots are used in the real-life world include:↓</em>

<em />

<em>1. The correlation between the height of an individual and their weight.</em>

<em></em>

<em>2. The correlation number of hours spent by a student in watching movies and his exam scores.</em>

<em></em>

<em>3. In Economics, scatterplots are also applicable in the correlation between inflation and retail sales of commodities.   </em>

  • Hope this helps!
  • Have a Wonderful Day!

\bold{-InLoveWithNature-}

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Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
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hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

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Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

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Answer:

m∠5 = 67

m∠7 = 67

Step-by-step explanation:

m∠4 and m∠5 add up to 180 because they are same side interior angles.

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