What is the solution to 3/4 a> -16?

1 answer:

7 0

Multiply the given equation by 4/3. This is a positive number, so the sense of the inequality remains the same.
A. a > -21 1/3

_____
When solving inequalities, the rules of equality hold, except when multiplying or dividing by a negative number (and when applying certain functions). In those cases, the direction of the inequality must be reversed. As a simple example, consider the inequality
2 > 1
When this is multiplied by -1, you get
-2 < -1 . . . . . > has changed to <

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10 3/9- 10 2/5 Im to lazy to do it please help me out.

coldgirl [10]

Answer:

$\boxed{ \ - \frac{3}{45} }$

Step-by-step explanation:

10 3/9 - 10 2/5

we need to convert mixed fractions to improper fractions

$10 \frac{3}{9} = \frac{10 \times 9 + 3}{9} = \frac{93}{9}$

$10 \frac{2}{5} = \frac{10 \times 5 + 2}{5} = \frac{52}{5}$

Now, we have 93/9 - 52/5

We need to equate the denominators, before subtracting them.

$\frac{93}{9} - \frac{52}{5} = \frac{93 \times 5}{45} - \frac{52 \times 9}{45}$

$\frac{465}{45} - \frac{468}{45}$

$\frac{ - 3}{45}$

$\boxed{ - \frac{3}{45} }$

The result of 10 3/9- 10 2/5 is - 3/45

8 0

1 year ago

Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter tha

raketka [301]

According to the developed scale, a radiant day is 16 times brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is 16 times brighter than a dim day.

Learn more about the developed scale at

brainly.com/question/4970963

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The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

8 0

1 year ago

A football team lost 5 yards on each 3 plays. explain how you could use a number line to find the team's change in field positio

ollegr [7]

A football team lost 5 yards on each 3 plays.
Let’s use a number line to be able to see how far in the field did they lost in 3 games.
=> 1 : 5 (1 game is to 5 yards)
=> 3 : 15 (3 games is to 15 yards )
All in all they lost 15 yards in 3 games.
pls. see attachment for more presentation.