The pounds of alloy that contains 26% copper that would be used is 23.42 pounds.
The pounds of alloy that contains 69% copper that would be used is 29.58 pounds.
<h3>What are the linear equations that represent the question</h3>
0.26a + 0.69b = (53 x 0.5)
0.26a + 0.69b = 26.50 equation 1
a + b = 53 equation 2
Where:
- a =pounds of alloy that contains 26% copper
- b = pounds of alloy that contains 69% copper
<h3>How many pounds of each alloy should be in the third alloy?</h3>
Multiply equation 2 by 0.26
0.26a + 0.26b = 13.78 equation 3
Subtract equation 3 from equation 2
12.72 = 0.43b
b = 12.72 / 0.43
b = 29.58 pounds
a = 53 - 29.58 = 23.42 pounds
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Answer:
The answer to your question is: c) $1354500
Step-by-step explanation:
Data:
Parcel1 = P1 = 1 mi2
Parcel2= P2= 5 acres
Price = $2100 / acre
Total price =
Need to convert 1 mi2 to acres
1 acre ------------------------ 0.001563 mi2
x ------------------------- 1 mi2
x = 639.8 acres
Now
1 acre ------------------------- $2100
639.8 acres ----------------- x
Parcel 1 cost = $1343580
1 acre ------------------------- $2100
5 acres --------------------- x
x = 10500
Total cost = cost P1 + cost P2
Total cost = $1343580 + $10500 = $ 1354080 The closest is letter c
Divide the numerator by the denominator
45/50= .9
multiply by 100
.9x100= 90%
Answer: 90%
Either a or b. C and d don’t make sense cuz there’s no way those lines are perpendicular
Answer:
1/12 5/12 11/12
Step-by-step explanation:
Um it was pretty obvious but...