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3 years ago

If u=f(x,y) where x=(e^s)(cos(t)) and y=(e^s)(sin(t)), show that (du/dx)^2 + (du/dy)^2 = (e^(-2s))((du/ds)^2+(du/dt)^2)) ...?

1 answer:

8 0

no usually the problem is set up this way f(x,y)= z if z= w/e ( it has an x and a y) where y= (something that has s and t) and x= ( something that has s and t) but your question does not make sense to me. Are you sure you wrote it right?

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8/21 fraction to decimal

katrin [286]

Answer:

Solution and how to convert 8 / 21 into a percentage

0.38 times 100 = 38.1. That's all there is to it!

Step-by-step explanation:

hope this helps

7 0

2 years ago

A surfboard is originally priced at $155. The online retailer gives a discount and the surfboard is now priced at $93. Enter the

GrogVix [38]

93 is 60 percent from the original price.
The discount reduces the original price by 40 percent.

7 0

3 years ago

Help me please 12 and f

zimovet [89]

Answer:

It is not equivalent.

Step-by-step explanation:

You have to expand the brackets :

(x-4)(x+3)

= x(x) + x(3) - 4(x) - 4(3)

= x² + 3x - 4x - 12

= x² - x - 12

Therefore, x² - x - 12 / (x-4)(x+3) is not equivalent to x² - 4x - 12.

6 0

3 years ago

A snail can travel 390 inches in 5 hours.<br> How far does it travel in 1 hour?

puteri [66]

78, divide 390 by 5 which equals 78

8 0

3 years ago

Read 2 more answers

A chemistry teacher needs to mix a 20% salt solution with an 80% salt solution to make 20 qt of a 40% salt solution. How many qu

Svetlanka [38]

Answer:

6 2/3 qt 80%
13 1/3 qt 20%

Step-by-step explanation:

It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.

We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...

0.80x +0.20(20-x) = 0.40(20)

0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify

x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution

(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed

The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.

3 0

2 years ago