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zubka84 [21]
3 years ago
10

PLEASE HELP ME ASAP!!!!! WILL GIVE BRAINLIEST!!! Solve the proof Thanks Y'all:))

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

Below.

Step-by-step explanation:

Triangles ABC and CDE are congruent by  2 angles and the corrrespnding side  (AAS).

Therefore  AC = CE.

So C is the midpoint of AE.

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Write the equation of the line y = 3x + 5 when dilated by a scale factor of 2 centered
Nostrana [21]

Answer:

Warm Up: Line y = 3x – 1 is transformed by a dilation with a scale factor of 2 ... Exercise 1- The line y = 3x is dilated by a scale factor of 2 and centered at the origin. ... 5. The line y=--x-2 is graphed to the right. Write the equation of the m=273.

Step-by-step explanation:

8 0
2 years ago
F) Two numbers are in the ratio 5:4. If they differ by 12, what are the numbers?
Iteru [2.4K]

Answer:

First number = 60 and another number = 48

Step-by-step explanation:

Let two numbers are 5x and 4x.

The two number are differ by 12. We need to find the numbers.

ATQ,

5x-4x = 12

x = 12

Now first number = 5x

= 5(12)

= 60

Other number = 4x

= 4(12)

= 48

Hence, the numbers are 60 and 48.

8 0
3 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST !!
8090 [49]

Answer:

2 and 6, 4 and 8, 1 and 5, 3 and 7

Step-by-step explanation:

The angle rule of corresponding angles states that the corresponding angles are equal if a transversal cuts two parallel lines.

In this example, lines m and l are two parallel lines

line n cuts through both, making every other angle corresponding and congruent, etc...

6 0
3 years ago
Read 2 more answers
Period of y=2tan (2x+90) -1
krek1111 [17]
20 is the answer
I hope this help
4 0
3 years ago
A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu
Mars2501 [29]

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

8 0
3 years ago
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