<span>To solve this equation we
can first assume that both a and b are nonzero real numbers. Hence,
A = 1 b = 1
<span><span>
1.
</span>2 (1) + 1 =
2(1)</span>
<span><span>
2.
</span><span> 2 + 1 = 2: now this a false equation since
there is not equality, the equation cannot retain the equal sign but will
become 2 + 1 > 2. Leaving the relationship unequal.
</span></span>However, the alternative to
this problem is to be b = 0. To oversee the rule in order to solve the equation
retaining it as an “equation”. Further, there is no other solution for this
equation.
A = 1 b = 0
<span>1.
Which
becomes 2(1) + 0 = 2(1)</span>
<span><span>
2.
</span><span> 2 + 0 = 2 :
3. 2 = 2. Here we can observe the
equality. </span></span>
</span>
Answer:
endo 2 17uni
Step-by-step explanation:
Answer:
Step-by-step explanation:
Sum: addition
Difference: subtraction
Product: multiplication
Number Sum Difference Product
1, 4 1 + 4 = 5 4 - 1 = 3 1 * 4 = 4
2, 8 2 + 8 = 10 8 - 2 = 6 2 * 8 = 16
Hope this helps!
Answer:
p = -
Step-by-step explanation:
- you have to simplify the left side of the problem first
- the 2 p's cancel each other out
- now you have to do order of operations
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
1/3-1 = p
p= -
There is not anything to use to answer with. i cannot provide any information to help since there is nothing to use
