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r-ruslan [8.4K]
3 years ago
8

What is the equation perpendicular to y= -1/5x +3 and goes through the point (7,4)?

Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

y - 4 = 5(x - 7) or y = 5x - 31

Step-by-step explanation:

Slope-intercept form: <em>y = mx + b</em> (m = slope, b = y-intercept)

Point-slope form: <em>y - y₁ = m(x - x₁)</em> ((x₁, y₁) = known point, m = slope)

1. Slope: perpendicular to -1/5 --> 5 (negative reciprocal)

2. Insert knowns into equation: y - 4 = 5(x - 7)

3. Turn into point-slope form (assuming that is what we are looking for):

Multiply: <em>y - 4 = 5x - 35</em>

Subtract: y = 5x - 31

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