In order to subtract fractions, we must find a common denominator, then subtract the numerators.
The common denominator (LCM(3, 5)) is 15.
We must multiply the first numerator by 5, because 3*5=15 and the second numerator by 3 because 5*3=15.
We get .
All we need to do now is subtract the numerators: .
The answer is 14/15.
The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
then the discontinuity point is at
.
Comptine the zeroes:
Set
Compute the discriminant:
Then with quadratic formula we get the solutions:
The two zeros are
So you just have to use distance formula
9514 1404 393
Answer:
yes
Step-by-step explanation:
The triangles are given as right triangles. Hypotenuses QT and RS are given as congruent.
We also have XS ≅ TP. By the addition property of equality, this means ...
XS +ST ≅ ST +TP
By the segment sum theorem, this means ...
XT ≅ SP
XT and SP are the corresponding legs of the right triangles. So, we have corresponding hypotenuses and corresponding legs congruent. This lets us conclude ΔXQT ≅ ΔPRS by the HL theorem.