Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
The answer is A.
If the submarine descended then it went below, and if it ascended it went above. Therefore:
"Descended 2 miles"= -2
"Then descended another 3 miles"= -3
(-2)+(-3)=-5
Adding two negatives together will give you a bigger negative so the submarine would then be 5 miles below its original location.
Answer:
35 bagels
Step-by-step explanation:
Duh
Answer:
Wat the heck?
Step-by-step explanation:
Is this hw cus I feel bad for ya!
