20 ÷ 2 (5,5)
20 ÷ 2 (25)
20 ÷ 50
.4
F(5) = 3(5) - 9 = 6
g o f (5) = g(6) = 6^2 = 36 answer
Answer: option A. 9.2 gal/year
Justification:
The average rate of change from 1960 to 1970 is the change on the variable gallons consumed per passenger car divided by the period
average rate of change = Δg / Δt
Δg = 760 gallons - 668 gallons
Δt = 1970 year - 1960 year
760 gal - 668 gal 92 gal
average rate of change = -------------------------------- = ---------- = 9.2 gal / year
1970 year - 1960 year 10 year
Answer: 9.2 gal / year
As you see for this specific period, 1960 to 1970, the vehicles increased their consumption of gas per passenge, meaning that they became less efficient.
No.
Since w = 8, you must replace the variable with the number associated to it.
So, it would be 5 + 8 = 58
5 + 8 is not equal to 58, it is equal to 13.
If you wanted to find out what w was, simply subtract 5 on both sides.
w = 58 - 5
