Question

If u=<-4,8> and v=<-7,5>, v-5u= ? and ||v-5u|| is approximately?

Answer 1

Answer:

Step-by-step explanation:

a) Given:

u=$\:$

v=<-7,5>

v-5u=<-7,5>-5<-4,8>

v-5u=<-7,5>+<20,-40>

v-5u=<-7+20,5-40>

v-5u=<13,-35>

b)

The magnitude of this vector is

||v-5u||=$\sqrt{13^2+(-35)^2}$

||v-5u||=$\sqrt{169+1225}$

||v-5u||=$\sqrt{1394}$

||v-5u||=$37.3units$ to the nearest tenth

Answer 2

Answer:

vvvvvvvvvvvvvvvvvvvvvvv

Step-by-step explanation: