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ASHA 777 [7]
3 years ago
9

Is w = 8 a solution to the equation 5 + w = 58? Explain

Mathematics
1 answer:
sp2606 [1]3 years ago
8 0

No.

Since w = 8, you must replace the variable with the number associated to it.

So, it would be 5 + 8 = 58

5 + 8 is not equal to 58, it is equal to 13.

If you wanted to find out what w was, simply subtract 5 on both sides.

w = 58 - 5

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Please help with a, b, and c!!
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(a). 
The product of two binomials is sometimes called FOIL.
It stands for ...

       the product of the First terms                (3j  x  3j)
plus
       the product of the Outside terms          (3j  x  5)
plus
       the product of the Inside terms            (-5  x  3j)
plus
       the product of the Last terms                (-5  x  5)

FOIL works for multiplying ANY two binomials (quantities with 2 terms).

Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .

Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.

Whenever you have     

              (the sum of two things) x (the difference of the same things)

the product is going to be

                 (the first thing)²  minus  (the second thing)² .

So in (a), that'll be      (3j)² - (5)²  =  9j² - 25 .

You could find the product with FOIL, or with this easier tool.
______________________________

(b).
This is the square of a binomial ... multiplying it by itself.  So it's
another product of 2 binomials, that both happen to be the same:

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You can do the product with FOIL, or use another little tool:

The square of a binomial        (4h + 5)²    is ...

         the square of the first term               (4h)²
plus
         the square of the last term                (5)²
plus
         double the product of the terms      2 · (4h · 5)
________________________________

(c).
Use the tool I gave you in part-a . . . twice .

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The product of the last 2 binomials is also    (g² - 4) .

Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .

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3 years ago
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