Answer:
The person has been dead for approximately 15,300 years
Explanation:
<u>Available data</u>:
- The half-life of carbon 14 is 5,600 years
- The human skeleton level of carbon 14 is 15% that of a living human
To answer this question we can make use of the following equation
Ln (C14T₁/C14 T₀) = - λ T₁
Where,
- C14 T₀ ⇒ Amount of carbon in a living body at time 0 = 100%
- C14T₁ ⇒ Amount of carbon in the dead body at time 1 = 15%
- λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
- T₀,₅ ⇒ The half-life of carbon 14 = 5600 years
- T₀ = 0
- T₁ = ???
Let us first calculate the radioactive decay constant.
λ = (Ln2)/T₀,₅
λ = 0.693/5600
λ = 0.000123
Now, let us calculate the first term in the equation
Ln (C14T₁/C14 T₀) = Ln (15%/100%) = Ln 0.15 = - 1.89
Finally, let us replace the terms, clear the equation, and calculate the value of T₁.
Ln (C14T₁/C14 T₀) = - λ T₁
- 1.89 = - 0.000123 x T₁
T₁ = - 1.89 / - 0.000123
T₁ = 15,365 years
The person has been dead for approximately 15,300 years
A, b , and c are true. The monomer of sugar polymers is monosaccharides
Answer:
Hi What is the perimeter of this polygon?
A
−11f−8d−11
B
−f+5d−3d−3f
C
f−3+6d
D
2d−4fWhat is the perimeter of this polygon?
A
−11f−8d−11
B
−f+5d−3d−3f
C
f−3+6d
D
2d−4f
Explanation:
Since the person is diagnosed and has been confirmed of having anti-social personality disorder, it means the patient does not have any thought of what is right and wrong and that the individual will likely ignore the feelings of others by that the nurse should still understand what the patient is going through and politely answer in a way that won't affect the client and in the same time, the nurse shouldn't be affected with what the client told him or her.
