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chubhunter [2.5K]
4 years ago
13

Jeffrey earned $65 doing yard work he bought a pair of jeans for 3125 and a sweatshirt for 1650 he set aside the money left from

his shopping trip to buy a gift for his cousin how many money did he set aside for the gift
Mathematics
1 answer:
kogti [31]4 years ago
6 0
Jeffrey set aside 12.25 for a gift.
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What is the answer to the question down below
N76 [4]

Answer:

I'm pretty sure the answer is 4

Step-by-step explanation:

Because SQ is 4 and it looks like QT is the same length

6 0
2 years ago
Layna can paint a 350-square foot room in 4 hours. It takes Bebe 7 hours to paint the same room. Which equation can be used to f
ohaa [14]

The equation can be used to find the time in hours, \dfrac{t}{4}+\dfrac{t}{7}=1 and the time will be 2.5 hours. So the correct answer is option A.

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Layna can paint a 350-square-foot room in 4 hours.It takes Bebe 7 hours to paint the same room.

Let t be the total time taken by both to paint.They are completing 1 job so the equation will be :

\dfrac{t}{4}+\dfrac{t}{7}=1

Further solving it we get;

7 t + 4 t = 28

11t  =  28

t = 2.5 hours.

Therefore the equation can be used to find the time in hours, \dfrac{t}{4}+\dfrac{t}{7}=1 and the time will be 2.5 hours. So the correct answer is option A.

To know more about equations follow

brainly.com/question/2972832

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8 0
2 years ago
The lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 h
DaniilM [7]

Answer:

Probability that a battery will last more than 19 hours is 0.0668.

Step-by-step explanation:

We are given that the lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 hours.

<em>Let X = lifetime of a battery in a certain application</em>

So, X ~ N(\mu=16,\sigma^{2} =2^{2})

The z-score probability distribution for normal distribution is given by;

               Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean lifetime = 16 hours

            \sigma = standard deviation = 2 hours

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a battery will last more than 19 hours is given by = P(X > 19 hours)

  P(X > 19) = P( \frac{  X -\mu}{\sigma} > \frac{19-16}{2} ) = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                              = 1 - 0.9332 = 0.0668

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.</em>

Hence, the probability that a battery will last more than 19 hours is 0.0668.

5 0
4 years ago
The number of measles cases increased 13.6 % to 57 cases this year, what was the number of cases prior to the increase? (Express
ELEN [110]

Answer:

The number of cases prior to the increase is 50.

Step-by-step explanation:

It is given that the number of measles cases increased by 13.6% and the number of cases after increase is 57.

We need to find the number of cases prior to the increase.

Let x be the number of cases prior to the increase.

x + 13.6% of x = 57

x+x\times \frac{13.6}{100}=57

x+0.136x=57

1.136x=57

Divide both the sides by 1.136.

\frac{1.136x}{1.136}=\frac{57}{1.136}

x=50.176

x\approx 50

Therefore the number of cases prior to the increase is 50.

7 0
3 years ago
Help pls!
4vir4ik [10]

Answer:

the probability that the next gumball that comes out will be neither yellow nor blue = 6/17

Step-by-step explanation:

neither yellow nor blue gumball = pink gumball = 6

3 yellow + 8 blue + 6 pink = total =17

3 0
3 years ago
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