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Svetllana [295]
3 years ago
9

What is 95.833 (three repeating) as a fraction?

Mathematics
2 answers:
Mariana [72]3 years ago
7 0

Answer:

575/6


Step-by-step explanation:



Alinara [238K]3 years ago
7 0

Answer:

575/6


Step-by-step explanation:

we know 1/3 is 0.33333...

95.83333 = 95.83333 - 0.3333 + 1/3

= 95.5 + 1/3 = 95 + 1/2 + 1/3

= 95 + 5/6 = (95×6 + 5)/6

= (600-30+5)/6 = 575/6

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-7,-3,1,5,9
Serggg [28]

-7 + 4(n-1).  Use this and plug in 10 for n, making it

-7 + 4(9)

-7+36

29

5 0
2 years ago
Pleaseeeeee help me i appreciate it​
4vir4ik [10]

Answer:

Choice A (older trees are generally taller than younger trees)

Step-by-step explanation:

As you increase the x value, the y value tends to increase as well.  Choice B is incorrect because the points are clustered together in a linear fashion, showing correlation. Choice C is incorrect because the fact that they are clustered around a line of best fit shows high correlation. Choice D is incorrect because a negative correlation coefficient would mean the y decreases as x increases.

7 0
3 years ago
Factor x^2+6x-16 into the form (x+a)(x-b), what is a and b?
vfiekz [6]

Answer:

a=-8 b=2

Step-by-step explanation:

x^2+6x-16

x^2+(8-2)x-16=0

x^2+8x-2x-16=0

X(X+8)-2(X+8)=0

(X+8)(x-2)=0

Compare with (X+a)(X+b)

Where we get a=-8 b=2

8 0
3 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
3 years ago
Jackson is playing a video game that has 4 castles to conquer within each level. Jackson has completed 6 levels so far. If x rep
Alenkinab [10]
Each level has 4 castles to conquered. Jackson completed 6.
Let x be the number of remaining levels and y is the total number of castles to defeat

For every x, there are 4 castles to conquered, 4x represents number of remaining levels and corresponding castles.

Since he has already conquered 6 levels 4(6) = 24 so
y=4x+24, A.
8 0
3 years ago
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