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Rama09 [41]
2 years ago
12

Ude the following rules to graph and label the ordered pairs on a coordinate grid with at least 4 points on the coordinate plane

:
Maddy and Ted worked together to graph ponts on a coordinate plane.
1. Maddy wrote a pattern for all the x coordinates starting at 3 and followed the rule add 2 2. Ted wrote a pattern for all the y coordinates starting at 0 and followed the rule add 4
Mathematics
1 answer:
Pavlova-9 [17]2 years ago
5 0

Answer:

y= 2/2x=3

ted= (0,4)

Step-by-step explanation:

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Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.
faltersainse [42]
f(x) = \frac{x + 4}{3x^{2} + 5x - 2}

                     3x² + 5x - 2 = 0
                3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
          3x(x + 2) - 1(x + 2) = 0
                  (3x - 1)(x + 2) = 0
3x - 1 = 0       or       x + 2 = 0
    + 1 + 1                     - 2  - 2 
     3x = 1          or          x = -2
      3     3                       1     1
       x = ¹/₃         or         x = -2

      f(x) = 3x² + 5x - 2
     f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
     f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
     f(¹/₃) = ¹/₃ - ¹/₃
     f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)

      f(x) = 3x² + 5x - 2
     f(-2) = 3(-2)² + 5(-2) - 2
     f(-2) = 3(4) - 10 - 2
     f(-2) = 12 - 12
     f(-2) = 0
(x, f(x)) = (-2, 0)

    Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
      Oblique Asymptote: No Asymptotes
3 0
3 years ago
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What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
uysha [10]
Radius=2
center(-2,4)
4 0
3 years ago
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I need help with this if anyone can help
Fiesta28 [93]

Answer: \Large\boxed{Fourth~Choice.~f(x)=2-i}

Concept:

Here, we need to know the power of imaginary numbers

i = √(-1)

i² = -1

i³ = -i

i⁴ = 1

Solve:

<u>Given function expression</u>

f(x)=x^3-2x^2

<u>Given the requirement of the question</u>

To find the expression for f(i)

<u>Substitute values into the expression</u>

f(x)=(i)^3-2(i)^2

<u>Simplify the exponents</u>

f(x)=(-i)-2(-1)

<u>Expand the parenthesis</u>

f(x)=-i-(-2)

\Large\boxed{f(x)=2-i}

Hope this helps!! :)

Please let me know if you have any questions

3 0
2 years ago
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Multiply.
alina1380 [7]

Answer:

2/4 or 1/2

Step-by-step explanation:

i used a numbers chart to break the numbers down.

5 0
2 years ago
Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems
Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for (x_{1},y_{1})  and (x_{2},y_{2})

Use the distance formula to find the length =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length =\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\

length = \sqrt{80}

length = 8.94

Use the distance formula to find the width =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width =\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\

width =\sqrt{(-10 )^{2} + (11 )^{2}}\\

width =\sqrt{100 + 121}\\

width = \sqrt{221}

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

7 0
2 years ago
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