Answer:
The correct answer is a cofactor for enzyme activity.
Explanation:
Carboxypeptidase is a metallo-enzyme in which zinc is present at active site. It has been accounted for by Coleman and Vallee that the protein can be deactivated by the removal of zinc and that reactive again by the expansion of zinc, cobaltous, ferrous, nickel. which suggests that zinc is acting as the cofactor for this metalloenzyme. Zinc is a cofactor for up to 300 chemicals in the body. Proteins that utilization zinc as a cofactor is known as metalloenzymes.
Thus, the correct answer is a cofactor for enzyme activity.
When a little curd is added to milk, the Lactobacillus bacteria present in the curd converts lactose sugar contained in milk into lactic acid.
The increased acidity in milk causes the protein, casein, to coagulate or form lumps, which leads to the formation of curds.
Answer:
The surface area of a sphere = 48 ²
Explanation:
Given:
The radius of a sphere = 2 meters
Use π = 3 (Approx)
Find:
The surface area of a sphere.
Computation:
⇒ The surface area of a sphere = 4πr²
⇒ The surface area of a sphere = 4(3)(2)²
⇒ The surface area of a sphere = 4(3)(4)
⇒ The surface area of a sphere = 48 meter²
The correct answer is: D) A and B only
Pneumonia is an inflammatory condition of the lungs that is usually caused by infection with viruses or bacteria. Pneumonia causes the fluid fill of the alveoli (air sacs). As a result symptoms such as cough with phlegm or pus, fever, chills, and difficulty breathing might occur. Pneumonia can be serious condition, especially for infants and people with weakened immune systems.
Answer:
The correct answer is - 2 genes.
Explanation:
The number of genes involved in the coloration of the strain of cereal grain, could be either dark tan, medium-dark tan, medium tan, light tan, or cream-colored if all F1 are medium tan when crossed a dark tan crossed with cream-colored, can be calculated as follow:
suppose there are only two gene - TT dominant over tt and CC dominant over cc
then the cross would be - RRCC - rrcc
gametes - RC and rc
Cross F1: RrCc
Self cross in F2:
offspring by Punnet cross are:
RRCC -->1/16
RRCc, RrCC .---> 4/16
RrCc, RRcc, rrCC--->6/16
rrCc, Rrcc--->4/16
rrcc ----> 1/16
thus, the correct answer is 2 genes
