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Alina [70]
2 years ago
9

Photopigment genes are located on the X chromosome. Color blindness occurs when an individual has missing or damaged alleles. A

woman who carries a damaged photopigment allele but has normal vision marries a man with normal vision. What is the probability that their son will be color blind
Biology
1 answer:
Hunter-Best [27]2 years ago
4 0

The probability that their son exhibits the 'color blind' trait is 0%. It is a type of inheritance linked to the X chromosome.

<h3>Inheritance linked to the X chromosome</h3>

In men, the patterns of inheritance linked to the X chromosome don't follow conventional mendelian inheritance because men have only one X chromosome.

Conversely, women have two X chromosomes, thereby the inheritance pattern resembles Mendelian inheritance.

It is important to highlight that color blindness is a recessive trait on the X chromosome.

In this case, the mother is a carrier, thereby the probability of passing this trait as a carrier to her son is 50%, whereas the father is normal, thereby the probability of passing this trait to his son is 0%.

Learn more about inheritance linked to the X chromosome here:

brainly.com/question/1020249

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Hemophilia is a x-linked recessive inherited bleeding  disorder. in this disease blood does not clot properly due to the decreased level of blood clotting factor VIII (8) or factor IX (9).

In x-linked recessive condition, the disease is transmitted from father (affected male) to his daughter and mother (affected female) to her son and skip of generation getting affected is also occurs.

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Hemophilia is caused due to mutation of one gene which is responsible for the making of proteins of  blood coagulation factor viii or ix. the affected person bleeds continuously from any injury and that can cause serious issues.

here,

grandfather of s.r is affected (xₐy) and grandmother is normal (xx) will produce

                                                   ↓

 s.r's mother who is a carrier (xₐx) [as xₐy and xx will produce 100% carrier xₐx daughter]

                                                    ↓

s.r's mother is a carrier (xₐx) but her father is normal (xy) will produce,

                                                   ↓

s.r who has 50% chance of being carrier (xₐx) and 50% chance of being normal (xx) [as she is the only child] and she has a normal (xy) partner, they will give,

                                                     ↓

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  2. if s.r is normal (xx) then her son will be normal (xy) [as xx and xy will give xy]

here,<u> 50% chance of her son to be affected with hemophilia</u> [as S.R of being affected is more considerable].

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