The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
<h3>Equation of a line</h3>
A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;
y - y1 = -1/m(x-x1)
where
m is the slope
(x1, y1) is the intercept
Given the following
Point = (4, -1)
Line: 2x-y - 7 = 0
Determine the slope
-y = -2x + 7
y= 2x - 7
Slope = 2
Substitute
y+1 = -1/2(x -4)
Write in slope-intercept form
2(y + 1) = -(x - 4)
2y+2 = -x + 4
2y = -x + 2
y = -1/2 + 1
Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
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Answer:
x=10
Step-by-step explanation:
hope it helps
Angle K = angle M
(4x-1)=(2x+27)
4x-2x=27+1
2x=28
x=14
K=4x-1 then 4(14)-1
55 degrees
M=2x+27 then 2(14) +27
55 degrees
K+M+L =180
55+55+L=180
110+L=180
L=70 degrees
Therefore K=55 degrees M=55 degrees L=70 degrees
The unit rate<span> is a comparison of two different quantities when they are combined together</span>
